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Bingel [31]
3 years ago
14

Marcel collects soccer cards. He has 24 cards in his collection. Four-sixths of his cards have been canceled. How many of the ca

rds in Marcel's collection have been canceled?
Mathematics
1 answer:
Salsk061 [2.6K]3 years ago
7 0
24 cards × 4/6 canceled

24 × 4/6 = 96/6 = 16 canceled
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Question #10 Evaluate the expression: 18-3(1+4)
Mashutka [201]

Answer:

18-3-12

15-12

3 is the answer

hope this helps

have a good day :)

Step-by-step explanation:

4 0
2 years ago
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A page should have perimeter of 42 inches. The printing area within the page
Tamiku [17]

Overall  dimensions of the page in order to maximize the printing area is  page should be 11 inches wide and 10 inches long .

<u>Step-by-step explanation:</u>

We have , A page should have perimeter of 42 inches. The printing area within the page  would be determined by top and bottom margins of 1 inch from each side, and the  left and right margins of 1.5 inches from each side. let's assume  width of the page be x inches  and its length be y inches So,

Perimeter = 42 inches

⇒ 2(x+y) = 42\\x+y = 21\\y = 21-x

width of printed area = x-3  & length of printed area = y-2:

area = length(width)

area = (x-3)(y-2)\\area = (x-3)(21-x-2)\\area = (x-3)(19-x)\\area = -x^{2} + 22x -57

Let's find \frac{d(area)}{dx}:

\frac{d(area)}{dx} = \frac{d(-x^{2}+22x-57)}{dx} = -2x +22 , for area to be maximum \frac{d(area)}{dx}= 0

⇒ -2x+22 = 0\\2x =22\\x=11 inches

And ,

y = 21-x\\y = 21-11\\y = 10 inches

∴ Overall  dimensions of the page in order to maximize the printing area is  page should be 11 inches wide and 10 inches long .

7 0
3 years ago
A scuba diver dives to a depth of 50 feet below sea level. To get a closer look at a hammer head shark, he ascends (goes up) 30
Julli [10]

Answer:

-70

Step-by-step explanation:

3 0
3 years ago
"the life length x (in years) of a dvd player" is exponentially distributed with mean 5 years. what is the probability that a mo
loris [4]
The exponential distribution is:
\lambda e^{- \lambda x}
where \lambda = \frac{1}{mean}=\frac{1}{5}

The probability we want is how likely will a dvd player last more than 8 years, given it has already lasted 5 years
To find this, you use conditional probability.
P(A|B) = \frac{P(A and B)}{P(B)}
where A is P(x>8) and B is P(x>5)
To find these probabilities, integrate over the distribution:
P(x \ \textgreater \ N) = \int_N^{\infty} \frac{1}{5} e^{-x/5} dx = e^{-N/5}

Sub into conditional probability formula:

P(x \ \textgreater \ 8 | x\ \textgreater \ 5) = \frac{P(x\ \textgreater \ 8)}{P(x\ \textgreater \ 5)} = \frac{e^{-8/5}}{e^{-5/5}} = e^{-3/5} = 0.549

Final Answer: Given a dvd player is more than 5 years old, the probability that it will last another 3 more years is about 54.9%
3 0
3 years ago
105 divided by 3<br> long division estimating please show your work
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35 I had this for a test the answer is

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2 years ago
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