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3 years ago

Which reasons explain why acids are added to foods? Check all that apply.

Chemistry

2 answers:

Tresset [83]3 years ago

4 0

Reduce spoilage and add zest or sour taste to food

Vika [28.1K]3 years ago

3 0

Explanation:

When food is left in atmosphere for a longer period of time then the oxygen in the atmosphere oxidizes the food leading to its spoilage.

As a result, the food becomes unfit for consumption.

Whereas when we add acid to our food then the acid helps in reducing growth of bacteria and microbes because on addition of acid pH of food also decreases.

Moreover, acids will add sour taste to food.

Thus, we can conclude that acids are added to foods because:

to reduce spoilage.

to add zest or sour taste to food .

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What is the molarity of a solution composed of 5.85 g of potassium iodide, KI, dissolved

Troyanec [42]

Answer:

0.282 M

General Formulas and Concepts:

Chemistry - Solutions

Reading a Periodic Table
Using Dimensional Analysis
Molarity = moles of solute / liters of solution

Explanation:

Step 1: Define

5.85 g KI

0.125 L

Step 2: Identify Conversions

Molar Mass of K - 39.10 g/mol

Molar Mass of I - 126.90 g/mol

Molar Mass of KI - 39.10 + 126.90 = 166 g/mol

Step 3: Convert

$5.85 \ g \ KI(\frac{1 \ mol \ KI}{166 \ g \ KI} )$ = 0.035241 mol KI

Step 4: Find Molarity

M = 0.035241 mol KI / 0.125 L

M = 0.281928

Step 5: Check

We are given 3 sig figs. Follow sig fig rules and round.

0.281928 M ≈ 0.282 M

7 0

3 years ago

Zinc blende, or sphalerite, can be described as having a face-centered cubic unit cell with sulfur atoms at each lattice point a

g100num [7]

Answer:

ZnS

Explanation:

1. Number of Zn atoms

4 internal atoms = 4 Zn atoms

2. Number of S atoms

8 corners × ⅛ S atom/corner + 6 faces × ½ S atom/face = 1 S atom + 3 S atoms = 4 S atoms

3. Empirical formula

The atomic ratio is

4Zn:4S = 1Zn:1S

The empirical formula is ZnS.

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3 years ago

How many grams are in 1.946 moles of NaCl

Elden [556K]

113.8g

................

5 0

2 years ago

Read 2 more answers

What volume of 0.4567 m h2so4 is required to neutralize 30.00 ml of 0.3210 m naoh?

sertanlavr [38]

Answer is: volume of H₂SO₄ is 42.1 mL.
Chemical reaction: H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O.
c(H₂SO₄) = 0,4567 M = 0,4567 mol/L.
V(NaOH) = 30 mL ÷ 1000 mL/L = 0,03 L.
c(NaOH) = 0,321 M = 0,321 mol/L.
n(NaOH) = c(NaOH) · V(NaOH).
n(NaOH) = 0,321 mol/L · 0,030 L.
n(NaOH) = 0,00963 mol.
From chemical reaction: n(H₂SO₄) : n(NaOH) = 1 : 2.
n(H₂SO₄) = 0,01926 mol.
V(H₂SO₄) = n(H₂SO₄) ÷ c(H₂SO₄).
V(H₂SO₄) = 0,01926 mol ÷ 0,4567 mol/L.
V(H₂SO₄) = 0,0421 L = 42,1 mL.

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