A box weighing 12,000 N is parked on a 36° slope. What will be the component of the weight parallel to the plane that balances f
1 answer:
Given :
A box weighing 12,000 N is parked on a 36° slope.
To Find :
What will be the component of the weight parallel to the plane that balances friction.
Solution :
The component of that will be parallel to the plane to balance friction is :
Therefore, component of force to balance friction is F sin 36° .
Hence, this is the required solution.
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Good morning.
We have:
Where j is the unitary vector in the direction of the y-axis.
We have that
We add the vector -a to both sides:
Therefore, the magnitude of b is 47 units.
We have:
Where j is the unitary vector in the direction of the y-axis.
We have that
We add the vector -a to both sides:
Therefore, the magnitude of b is 47 units.