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xeze [42]
3 years ago
11

A certain reaction with an activation energy of 185 kJ/mol was run at 505 K and again at 525 K . What is the ratio of f at the h

igher temperature to f at the lower temperature
Chemistry
1 answer:
frosja888 [35]3 years ago
5 0

Answer:

The ratio of f at the higher temperature to f at the lower temperature is 5.356

Explanation:

Given;

activation energy, Ea = 185 kJ/mol = 185,000 J/mol

final temperature, T₂ = 525 K

initial temperature, T₁ = 505 k

Apply Arrhenius equation;

Log(\frac{f_2}{f_1} ) = \frac{E_a}{2.303 \times R} [\frac{1}{T_1} -\frac{1}{T_2} ]

Where;

\frac{f_2}{f_1}  is the ratio of f at the higher temperature to f at the lower temperature

R is gas constant = 8.314 J/mole.K

Log(\frac{f_2}{f_1} ) = \frac{E_a}{2.303 \times R} [\frac{1}{T_1} -\frac{1}{T_2} ]\\\\Log(\frac{f_2}{f_1} ) = \frac{185,000}{2.303 \times 8.314} [\frac{1}{505} -\frac{1}{525} ]\\\\Log(\frac{f_2}{f_1} ) = 0.7289\\\\\frac{f_2}{f_1}  = 10^{0.7289}\\\\\frac{f_2}{f_1}  = 5.356

Therefore, the ratio of f at the higher temperature to f at the lower temperature is 5.356

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Debora [2.8K]

Explanation:

1 mol = 22.4 l

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7 0
3 years ago
How many moles of nacl are required to make 250 ml of a 3.00 m solution?
choli [55]
The molarity is calculated using the following rule:
molarity = number of moles of solvent / volume of solution (in liters)

We have the volume of solution = 250 ml = 0.25 liters and the molarity = 3 m

Substituting in the equation, we get:
3 = number of moles / 0.25
number of moles = 3 x 0.25 = 0.75 moles
4 0
3 years ago
15. The mass of a sample of iron is 114 g, and the density of iron is 7.86 g/cm3. What is the volume of this iron sample?
anyanavicka [17]

Answer:

The answer is

<h2>14.50 cm³</h2>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

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From the question

mass of iron = 114 g

density = 7.86 g/cm³

The volume is

volume =  \frac{114}{7.86}  \\  = 14.50381679

We have the final answer as

<h3>14.50 cm³</h3>

Hope this helps you

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Answer:

B)

Explanation:

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A 23.9g object was submerged into 50.5ml of water. If the water rose to 89.4ml then what is the object's density?
timama [110]

Answer:

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Explanation:

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