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AfilCa [17]
3 years ago
15

.A person is unable to see distinctly the objects placed at large distances but is able to read a book comfortably. Name the def

ect of vision he is suffering from
Chemistry
1 answer:
GaryK [48]3 years ago
7 0

Answer:

The defect of vision suffered by the person is Myopia

Explanation:

The person can't see farther objects but is able to read a book which is placed closely to the eyes, using these observations the person is suffering from MYOPIA(nearsightedness) in which observer see close objects clearly but farther objects appear blurred.

The light entering the eye isn't correctly bent, the eyeball becomes big , or the eye lens become too converging, which converges the light ray in front of the cornea

This defect can be cured by using concave lenses.

You might be interested in
Select the correct answer.
Phoenix [80]

Answer:

Molecular formula =  C₆H₁₂O₆

Explanation:

Given data:

Mass of hydrogen = 31.7 g

Mass of carbon = 283.4 g

Mass of oxygen = 377.4 g

Molar mass of compound = 176.124 g/mol

Molecular formula = ?

Solution:

Number of gram atoms of H = 31.7 / 1.01 = 31.4

Number of gram atoms of O = 377.4 / 16 = 23.6

Number of gram atoms of C = 283.4 / 12 = 23.6

Atomic ratio:

            C                      :      H                 :         O

           23.6/23.6         :     31.4/23.6     :       23.6/23.6

              1                      :        1.33              :        1

C : H : O =3 (1 : 1.33 : 1 )

Empirical formula is C₃H₄O₃.

Molecular formula:

Molecular formula = n (empirical formula)

n = molar mass of compound / empirical formula mass

Empirical formula mass  = 3×12+4+3×16 = 88

n = 176.124 / 88

n = 12

Molecular formula = n (empirical formula)

Molecular formula = 2 (C₃H₄O₃)

Molecular formula =  C₆H₁₂O₆

7 0
3 years ago
Which best explains why the auricle is bent and folded?
andrey2020 [161]

Answer:

to increase the surface area

Explanation:

dk not that sure but hope it helps

4 0
3 years ago
During the summer after your first year at Carnegie Mellon, you are lucky enough to get a job making coffee at Starbucks, but yo
Studentka2010 [4]

Answer:

The answer is "36.76  ml "

Explanation:

In the given question, Its basic understanding to also be hired seems to be that coffee heat = heat that the milk absorbs  

The following relationship defines heat:

\to q = m C_{p}( T_2 - T_1)

Its updated equation is:

\to q_{\ coffee} = - q_\ milk} \\\\ \to m_{\ milk} C_{p} (T_2 - T_1)_{\ coffee} = - m_{ \ milk} C_{p} (T_2 - T_1)_{\ milk} ..........(a)

The following information is provided to you as per the question:  

1) Milk and coffee have the same heat power  

2) Difference in coffee temperature is:

\to (T_2 - T_1)_{\ coffee} = 75.0^{\circ} \ \ C-85.0^{\circ} \ \ C

                              = -10.0 ^{\circ} \ \ C

3) The difference in milk temperature:

\to (T_2 - T_1)_{ \ milk} = 75.0^{\circ} \ \ C- 7.0^{\circ} \ \ C

= 68.0 ^{\circ} \ \ C

4)  Milk and coffee density are equal therefore, weight and volume are equal and have same ratio, that can be shown as follows:

\to \ Density (\rho) =\frac{ \ Mass (m)}{ \ Volume (V)} \\\\\to m= V \times  \rho \\\\

\to m_{\ coffee} \times (T_2 - T_1)_{ \ coffee}= -m_{\ milk} \times (T_2 - T_1)_{milk} \\\\\to V_{\ coffee} \times  \rho_{\ coffee} \times (T_2 - T_1)_{\ coffee} = - V_{\ milk} \times  \rho_{\ milk} \times (T_2 - T_1)_{\ milk} \\\\\to V_{\ coffee} \times (T_2 - T_1)_{\ coffee} = - V_{\ milk} \times (T_2 - T_1)_{\ milk}.............(b)

by replace the equation values (b) for calculating milk volumes as shown as follows:

\to V_{\ coffee} \times (T_2 - T_1)_{\ coffee} = - V_{\ milk} \times (T_2 - T_1)_{\ milk}\\\\\to 250 ml \times (-10 .0^{\circ} \ \ C) =  - V_{\ milk} \times (68.0^{\circ} \ \ C)\\\\\to V_{\ milk}= \frac{250 ml \times (-10 .0^{\circ} \ \ C) }{- (68.0^{\circ} \ \ C)}

               = 36.76 \ ml

4 0
3 years ago
Two balls are at the same time height and released at the same time. One ball is dropped and hits the ground 5 s later. The othe
marusya05 [52]

Answer:the other ball hits the ground

15 seconds later

Explanation:

7 0
3 years ago
A sample of gas occupies a volume of 445 mL at a temperature of 274 K. At what temperature will this sample of gas occupy a volu
Ksenya-84 [330]
V1 = 445ml V2 = 499ml
T1 = 274 K T2 = ?

By Charles Law,
V1/T1 = V2/T2
445/274 = 499/T2
By solving we get,
T2 = 307.25 K
4 0
3 years ago
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