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aleksley [76]
3 years ago
9

What is the formula mass of

Chemistry
1 answer:
NeTakaya3 years ago
4 0

Answer:

the second one

Explanation:

because i did the test

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Water’s unique properties, high heat capacity, high density, solid phase less dense than liquid phase can be attributed to
Xelga [282]

Answer:

B- The polarity of the molecules and hydrogen bonding between molecules.

Explanation:

Hope this helps:)

4 0
2 years ago
100 POINTS!!!!<br><br> Please I need this page done lol
Alenkinab [10]

Answer:

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5 0
3 years ago
How do you find the pressure in a container if you don't have the temperature? 
BARSIC [14]
It depends on the process.
Like for example if the process is isothermal(temperature is constant), you can use,
PV = constant or P1V1 = P2V2 where P1V1 are initial conditions and P2V2 are final.


For adiabatic process,

PV^gamma = constant or P1V1 ^gamma = P2V2 ^gamma.

where gamma = Cp
                          ------
                           Cv
Cp = specific heat at constant pressure and Cv = specific at constant volume.

Value of Gamma will be given in question.
Hope this helps!


7 0
2 years ago
DUE IN 1 MINUTE HELP I'M DESPERATE
alexira [117]
I believe the answer is A.
6 0
2 years ago
Read 2 more answers
Calculate the change in entropy when 1.00 kg of water at 100 ∘C is vaporized and converted to steam at 100 ∘C. Assume that the h
andrew11 [14]

Answer : The change in entropy is 6.05\times 10^3J/K

Explanation :

Formula used :

\Delta S=\frac{m\times L_v}{T}

where,

\Delta S = change in entropy = ?

m = mass of water = 1.00 kg

L_v = heat of vaporization of water = 2256\times 10^3J/kg

T = temperature = 100^oC=273+100=373K

Now put all the given values in the above formula, we get:

\Delta S=\frac{(1.00kg)\times (2256\times 10^3J/kg)}{373K}

\Delta S=6048.25J/K=6.05\times 10^3J/K

Therefore, the change in entropy is 6.05\times 10^3J/K

5 0
2 years ago
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