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zloy xaker [14]
3 years ago
7

A number minus 3 is at least -5

Mathematics
2 answers:
alexandr1967 [171]3 years ago
5 0

Answer

Step-by-step explanation:

jtjyyk7uhg2 years ago
0 0

a number minus 3 is at least –5

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Using right triangle below find the sine of angle B
Reil [10]

Answer:

1/2

Step-by-step explanation:

sin = opposite/hypotenuse, so

sin(B) = \frac{\sqrt{7} }{2\sqrt{7} } = 1/2

7 0
3 years ago
Read 2 more answers
A small military base housing 1,000 troops, each of whom is susceptible to a certain virus infection. Assuming that during the c
slava [35]

Answer:

I=\frac{1000}{exp^{0,806725*t-0.6906755}+1}

Step-by-step explanation:

The rate of infection is jointly proportional to the number of infected troopers and the number of non-infected ones. It can be expressed as follows:

\frac{dI}{dt}=a*I*(1000-I)

Rearranging and integrating

\frac{dI}{dt}=a*I*(1000-I)\\\\\frac{dI}{I*(1000-I)}=a*dt\\\\\int\frac{dI}{I*(1000-I)}=\int a*dt\\\\-\frac{ln(1000/I-1)}{1000}+C=a*t

At the initial breakout (t=0) there was one trooper infected (I=1)

-\frac{ln(1000/1-1)}{1000}+C=0\\\\-0,006906755+C=0\\\\C=0,006906755

In two days (t=2) there were 5 troopers infected

-\frac{ln(1000/5-1)}{1000}+0,006906755=a*2\\\\-0,005293305+0,006906755=2*a\\a = 0,00161345 / 2 = 0,000806725

Rearranging, we can model the number of infected troops (I) as

-\frac{ln(1000/I-1)}{1000}+0,006906755=0,000806725*t\\\\-\frac{ln(1000/I-1)}{1000}=0,000806725*t-0,006906755\\-ln(1000/I-1)=0,806725*t-0.6906755\\\\\frac{1000}{I}-1=exp^{0,806725*t-0.6906755}  \\\\\frac{1000}{I}=exp^{0,806725*t-0.6906755}+1\\\\I=\frac{1000}{exp^{0,806725*t-0.6906755}+1}

6 0
2 years ago
What does -3x + 7 + -6x t 9 equal
liberstina [14]

Answer:

-50x

Step-by-step explanation:

-6x times 9 which is -54x

-54x-3x = -57x

-54x+7

8 0
3 years ago
The lengths of the sides of a triangle are 3, 3, and the square root 3. Can the triangle be a right triangle?
Readme [11.4K]
First find the decimal equivalent of square root 3: SQRT(3) = 1.732 ( roughly)
 
If the base and height were each 3, then the hypotenuse would need to be:

3^2 + 3^2 = C^2
9 + 9 = C^2
18 = C^2
C = SQRT(18) = 4.24

This is larger than sqrt(3), so this cannot be a right triangle.


If one leg was 3 and the other leg was sqrt(3) then the hypotenuse would be:
3^2 + 1.73^2 = C^2
9 + 3 = C^2
12 = C^2
C = SQRT(12) = 3.46

This is larger than 3, this cannot be a right triangle.

The answer is b) no.





8 0
3 years ago
Read 2 more answers
ETHANHUNT HELP HERE WOULD BE APPRECIATED
labwork [276]
We know, Length of Image = Length of Object * Dilation factor, 

Just substitute your known values, 
Length of Image = 9 * 2 = 18

In short, Your Answer would be 18 cm

Hope this helps!
4 0
3 years ago
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