8) 21.504 liters of gas
9) 122.5 g
10) 6.022*10^23
Explanation:
8)
1 mole= 22.4 liters
to calculate the volume of gas of 0.960 moles of CH4
22.4*0.960/1
= 21.504 liters of gas
9)
2.0 mole*18.02 g/ 1 mole
=122.5 g
10)
2.0 l * 1 mole/22.4 l
6.022*10^23
Answer:
See explanation
Explanation:
Before the advent of the wave-particle duality theory proposed by Louis de Broglie, there was a sharp distinction between mater and waves.
However, Louis de Broglie introduced the idea that mater could display wave-like properties. Erwin Schrödinger developed this idea into what is now known as the wave mechanical model of the atom.
In this model, electrons are regarded as waves. We can only determine the probability of finding the electron within certain high probability regions within the atom called orbitals.
This idea has been the longest surviving atomic model and has greatly increased our understanding of atoms.
Answer:
12.32 L.
Explanation:
The following data were obtained from the question:
Mass of CH4 = 8.80 g
Volume of CH4 =?
Next, we shall determine the number of mole in 8.80 g of CH4. This can be obtained as follow:
Mass of CH4 = 8.80 g
Molar mass of CH4 = 12 + (1×4) = 12 + 4 = 16 g/mol
Mole of CH4 =?
Mole = mass/Molar mass
Mole of CH4 = 8.80 / 16
Mole of CH4 = 0.55 mole.
Finally, we shall determine the volume of the gas at stp as illustrated below:
1 mole of a gas occupies 22.4 L at stp.
Therefore, 0.55 mole of CH4 will occupy = 0.55 × 22.4 = 12.32 L.
Thus, 8.80 g of CH4 occupies 12.32 L at STP.