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damaskus [11]
3 years ago
15

A can of chicken broth contains 340 mg of sodium chloride in 286.7 g of broth. What is the percent by mass of sodium chloride in

the broth?
Chemistry
2 answers:
rosijanka [135]3 years ago
4 0

Answer:

The percent by mass of sodium chloride in the broth is 0.118 %

Explanation:

Step 1: Data given

Mass of sodium chloride = 340 mg = 0.340 grams

Mass of broth = 286.7 grams

Step 2: Calculate the total mass

Total mass = mass of sodium chloride + mass of broth

Total mass = 0.340 grams + 286.7 grams

Total mass =287.04 grams

Step 3: Calculate percent by mass of sodium chloride

% mass NaCl = (mass NaCl / total mass) *100%

% mass NaCl = (0.340 grams / 287.04 grams) *100 %

% mass NaCl = 0.118 %

The percent by mass of sodium chloride in the broth is 0.118 %

marshall27 [118]3 years ago
3 0

Answer:

0.12 & of NaCl

Explanation:

Determine the percentage of NaCl in the broth

First of all, we convert the mass from mg to g

340 mg . 1g/ 1000 mg = 0.340 g

Now  we can calculate the %

(0.340 g / 286.7 g) . 100 = 0.12 %

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Suppose that you take 200 mg of an antibiotic every 8 hr. The​ half-life of the drug is 8 hr​ (the time it takes for half of the
DochEvi [55]

Answer:

600 mg

Explanation:

The initial amount of the drug = 200 mg

The half-life of the drug = 8 hrs

It means that:-

After 6 hours, the concentration becomes :- \frac{200}{2} mg

After 12 hours, the concentration becomes :- \frac{200}{4} mg

After 18 hours, the concentration becomes :- \frac{200}{8} mg

And so on...

Thus,

After infinite time = 200+\frac{200}{2}+\frac{200}{4}+\frac{200}{8}+..

Thus,

After infinite time = 200\times (1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+..)

The sum of the infinite series is:- 1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+.. = \frac{1}{1+\frac{1}{2}}=2

So,

<u>After infinite time = 200\times 2 mg = 600 mg</u>

5 0
3 years ago
What is the pH at the equivalence point in the titration of a 25.7 mL sample of a 0.370 M aqueous nitrous acid solution with a 0
expeople1 [14]

Answer:

pH = 8.24

Explanation:

Nitrous acid (HNO₂) reacts with KOH, thus:

HNO₂ + KOH → KNO₂ + H₂O

Moles of HNO₂ are:

0.0257mL ₓ (0.370mol / L) = 0.00951moles.

In equivalence point, the complete moles of nitrous acid reacts with KOH producing potassium nitrite. There are needed:

0.00951mol ₓ (1L / 0.491mol) = 0.01937L ≡ 19.4mL of 0.491M KOH to reach equivalence point.

Total volume in equivalence point is: 19.4mL + 25.7mL = <em>45.1mL</em>

Potassium nitrite is in equilibrium with water, thus:

NO₂⁻ + H₂O ⇄ HNO₂ + OH⁻

Where equilibrium constant, Kb, is defined as:

Kb = 1.41x10⁻¹¹ = \frac{[OH^-][HNO_2]}{[NO_2]}

In equilibrium, molarity of each compound are:

[NO₂⁻]: 0.00951mol/0.00451L - X = 0.211M - X

[HNO₂]: X

[OH⁻]: X

<em>Where X is reaction coordinate</em>

Replacing in Kb:

1.41x10⁻¹¹ = \frac{[X][X]}{[0.211 -X]}

0 = X² + 1.41x10⁻¹¹X - 2.97x10⁻¹²

Solving for X:

X = -1.72x10⁻⁶ <em>FALSE ANSWER. There is no negative concentrations.</em>

X = 1.72x10⁻⁶. <em>Right answer.</em>

That means:

[OH⁻]: 1.72x10⁻⁶M

As pOH is -log [OH⁻] and pH = 14-pOH:

pOH = 5.76; <em>pH = 8.24</em>

3 0
3 years ago
In a given population, which members are most likely to survive and produce offspring?
Aneli [31]

Answer:

Those individuals with advantageous traits are more likely to survive and reproduce. The survivors pass down these advantageous traits to their offspring.

Explanation:

8 0
2 years ago
Which of the following statements about the carbon cycle is NOT true?
nalin [4]

Answer:

Plants consume carbon through transpiration

Explanation:

In transpiration, plants lose water vapor through the stomata in their leaves. No carbon is involved in transpiration, which has an outbound direction. Nothing can be consumed through the stomata when vapor is going out of the plant. It´s like trying to get in through the exit.

3 0
3 years ago
Read 2 more answers
Fumaric acid, which occurs in many plants, contains, by mass, 41.4% carbon, 3.47% hydrogen, and 55.1% oxygen. The molecular mass
lukranit [14]

Answer:

Explanation:

C = 41.4/12 = 3.43

H = 3.47/1 = 3.47

O = 55.1/16 =3.44

CHO is the skeletal formula (divide each by the lowest number above). The results are close enough to 1 to be 1.

(CHO)_x = 116

C + H + O = 29

(29) _ x = 116

x = 116/29

x = 4

So there area 4 carbons 4 hydrogens and 4 oxygens.

The correct formula is C4H4O4

3 0
2 years ago
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