Answer:
Protein Concentration is 2.82mg/L
Explanation:
According to Beer-Lambert's Law, Absorbance is directly proportional to the concentration.
However, the concentration of a solution can be determined from a calibration curve, in which Absorbance is plotted on the y-axis and the Concentration on the x-axis.
Plotting the best line, the equation of line is used
y = mx + c
where y is absorbance = 0.150
m is slope = 0.0163
x is concentration
c is intercept = 0.104
inserting the values from the question
y = mx + c
0.150 = 0.0163x + 0.104
0.0163x = 0.150 - 0.104
0.0163x = 0.046
Divide both sides by 0.0163
0.0163x/0.0163 = 0.046/0.0163
x = 2.82
Concentration of protein = 2.82 mg/L
Answer:
The problem is solvable
Explanation:
The information that is provided, together with some equations are enough to solve the problem:
- The inlet states are totally defined.
- A heat balance under adiabatic assumption, allows to calculate the outlet temperature (both outlets stream are in equilibrium, so at the same temperature).
- The rule of phases implies that por the two-phase equilibrium, there is only one pressure for each temperature.
- The mass balance and equilibrium relationships allows to calculate the res of properties for the outlet streams.
A 0 Charge. Neutron are neutral in terms of charge
Answer:Determine the mass of the substance, and its molar mass. Divide the given mass by its molar mass to get moles, then multiply times 6.022 × 1023molecules 1mol.
Explanation:
<u>Answer:</u> C) be hypertonic to Tank B.
<u>Explanation: </u>
<u>
The ability of an extracellular solution to move water in or out of a cell by osmosis</u> is known as its tonicity. Additionally, the tonicity of a solution is related to its osmolarity, which is the <u>total concentration of all the solutes in the solution.
</u>
Three terms (hypothonic, isotonic and hypertonic) are used <u>to compare the osmolarity of a solution with respect to the osmolarity of the liquid that is found after the membrane</u>. When we use these terms, we only take into account solutes that can not cross the membrane, which in this case are minerals.
- If the liquid in tank A has a lower osmolarity (<u>lower concentration of solute</u>) than the liquid in tank B, the liquid in tank A would be hypotonic with respect to the latter.
- If the liquid in tank A has a greater osmolarity (<u>higher concentration of solute</u>) than the liquid in tank B, the liquid in tank A would be hypertonic with respect to the latter.
- If the liquid in tank A has the same osmolarity (<u>equal concentration of solute</u>) as the liquid in tank B, the liquid in tank A would be isotonic with respect to the latter.
In the case of the problem, option A is impossible because the minerals can not cross the membrane, since it is permeable to water only. There is no way that the concentration of minerals decreases in tank A, so <u>the solution in this tank can not be hypotonic with respect to the one in Tank B. </u>
Equally, both solutions can not be isotonic and neither we can say that the solution in tank A has more minerals that the one in tank B because the liquid present in tank B is purified water that should not have minerals. Therefore, <u>options B and D are also not correct.</u>
Finally, the correct option is C, since in the purification procedure the water is extracted from the solution in tank A to obtain a greater quantity of purified water in tank B. In this way, the solution in Tank A would be hypertonic to Tank B.