Answer:
9.308
Explanation:
The computation of the pH of the given solution is shown below:
But before we need to determine the HI molarity which is
= 0.1852 M
Now
As we know that
So,
Now the molarity of 
left is
= 0.397 - 0.1852
= 0.2118
= 4.692
Now as we know that
pH = 14 - pOH
= 14 - pOH
= 14 - 4.692
= 9.308
We simply applied the above equations
Answer:
1.53 L
Explanation:
Step 1: Given data
- Mass of oxygen (m): 11.2 g
- Ideal gas constant (R): 0.0821 atm.L/mol.K
Step 2: Calculate the moles (n) corresponding to 11.2 g of oxygen
The molar mass of oxygen is 32.00 g/mol.
11.2 g × (1 mol/32.00 g) = 0.350 mol
Step 3: Calculate the volume of oxygen
We will use the ideal gas equation.
P × V = n × R × T
V = n × R × T / P
V = 0.350 mol × (0.0821 atm.L/mol.K) × 415 K / 7.78 atm
V = 1.53 L
Answer: To show the number of atoms present.
Explanation: As in CO² (Carbon dioxide), there is a small 2 next to the symbol "O" (oxygen) to explain that there are two oxygen atoms.
