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Sladkaya [172]
3 years ago
7

What is uniform acceleration

Physics
1 answer:
kotegsom [21]3 years ago
5 0

Answer:

It means zero acceleration.

Explanation:

When a body moves with constant velocity then it is said to be there is no rate of change of velocity takes place because it is constant. So the acceleration becomes zero or uniform acceleration.

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Water is stored in 5 places on earth.Name each place an dnote the phrase that water is in liquid solid,gas
podryga [215]
Atmosphere - gas
sea and oceans - liquid and solid
land -liquid and solid
living things and plants - liquid


6 0
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What is the net force acting on a 52 kg object that has a velocity of 8.0 m/s and is moving in a circle of radius 1.6 m? a. 4000
jenyasd209 [6]
Σf = m a
Σf = m v^2 / r
Σf = 52 8^2 / 1.6
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Which is more dense, cold freshwater or warm seawater?
svp [43]
Cold freshwater<span> is </span>denser<span> than </span>warm seawater<span>, because of the salinity and temperature variations. Cold water would have less salt since the solubility of the salt is lower as compared to warm water. Hope this answers the question. Have a nice day.</span>
4 0
3 years ago
Read 2 more answers
A car is traveling at a constant speed on the highway. Its tires have a diameter of 65.0 cm and are rolling without sliding or s
lesya692 [45]

Answer:

Explanation:

The car is rolling without slipping so Vcm= R×ω = 0.325×49 = 16

4 0
3 years ago
A certain unfiltered full-wave rectifier with 120 V, 60 Hz input produces an output with a peak of 15 V. When a capacitor-input
KATRIN_1 [288]

Answer:

The peak-to-peak ripple voltage = 2V

Explanation:

120V and 60 Hz is the input of an unfiltered full-wave rectifier

Peak value of  output voltage = 15V

load connected = 1.0kV

dc output voltage = 14V

dc value of the output voltage of capacitor-input filter

where

V(dc value of output voltage) represent V₀

V(peak value of output voltage) represent V₁

V₀ = 1 - ( \frac{1}{2fRC})V₁

make C the subject of formula

V₀/V₁ = 1 - (1 / 2fRC)

1 / 2fRC = 1 - (v₀/V₁)

C = 2fR ((1 - (v₀/V₁))⁻¹

Substitute  for,

f = 240Hz , R = 1.0Ω, V₀ = 14V , V₁ = 15V

C = 2 * 240 * 1 (( 1 - (14/15))⁻¹

C = 62.2μf

The peak-to-peak ripple voltage

= (1 / fRC)V₁

= 1 /  ( (120 * 1 * 62.2) )15V

= 2V

The peak-to-peak ripple voltage = 2V

3 0
3 years ago
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