The correct answer is
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force per unit charge.
In fact, the electric field strength is defined as the electric force per unit charge experienced by a positive test charge located in the electric field. In formula:
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where
E is the electric field strength
F is the electric force experienced by the charge
q is the positive test charge.
As per Newton's 2nd law
we know that
it is product of mass and acceleration
here we know that
also we know that
so from above equation we have
so the force here will be 10020 N
Answer:
In this movement, both the magnitude and the direction of the force change
Explanation:
A body that moves in an elliptical path must be subjected to a force that is pointed towards one of the foci, therefore the force is central.
The magnitude of this force must be greater when the two bodies are closer and its directional changes, but it always points to the focus where the body that originates the force is.
In this movement, both the magnitude and the direction of the force change
Answer: 40m
Explanation: Distance is a function of speed/ velocity and time.
From the question the velocity along the z axis is given as 20 m/s at t = 0 secs We were ask to calculate the distance travelled when t = 2secs.
Recall that,
Velocity = distance travelled / time
Since we're calculating for distance we make it subject of formula;
Distance travelled = velocity * time
= 20m/s * 2s
= 40meter.
Answer:3.67 m/s
Explanation:
mass of block(m)=2 kg
Velocity of block=6 m/s
spring constant(k)=2 KN/m
Spring compression x=15 cm
Conserving Energy
energy lost by block =Gain in potential energy in spring
![2\left [ 6^2-v_2^2\right ]=2\times 10^3\times \left [ 0.15\right ]^2](https://tex.z-dn.net/?f=2%5Cleft%20%5B%206%5E2-v_2%5E2%5Cright%20%5D%3D2%5Ctimes%2010%5E3%5Ctimes%20%5Cleft%20%5B%200.15%5Cright%20%5D%5E2)
