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Natasha_Volkova [10]
2 years ago
14

Find the voltage across the 15 Ω resistor. . 35 Ω 20 Ω 15 Ω 10 V

Physics
1 answer:
almond37 [142]2 years ago
3 0

Answer:

35 Ω

Explanation:

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B. truthfully it's the only one that makes sense
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A sidereal day is the time it takes for
ch4aika [34]

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B. the stars to come back to the same positions in the sky.

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8 0
3 years ago
Which statement best explains the relationship between the electric force between two charged objects and the distance between t
spin [16.1K]
Unfortunately, the given statements are missing from the problem. However, we can still determine the relationship between the electric force between two objects and the distance between them. The formula for the electric force is given below:

F = (k*Q1*Q2)/d^2

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As seen in the formula, we can see that the electric force F is inversely proportional to the square of the distance between the two objects.
3 0
3 years ago
A 1.0-m-diameter vat of liquid is 2.0 m deep. The pressure at the bottom of the vat is 1.3 atm. What is the mass of the liquid i
gladu [14]

Answer:

The mass of the liquid = 10538 kg

Explanation:

The pressure in a liquid is

P = ρgh ......................... Equation 1

ρ = P/gh ...................... Equation 2

Where P = pressure, ρ = density, g = acceleration due to gravity, h = height.

Given: p = 1.3 atm, h = 2.0 m, g = 9.81 m/s²

If,  1 atm = 1.013×10⁵ N/m²

Then, P = 1.3×1.013×10⁵ N/m² = 1.3169×10⁵ N/m²

Substituting in equation 2,

ρ  =  1.3169×10⁵/(9.81×2)

ρ =   1.3169×10⁵/19.62

 ρ = 6712.03 kg/m³.

But Density,

ρ  = m/v  

m =  ρ × v........................ Equation 3

Where m = mass of the liquid, v = volume of the liquid in the vat

v = πd²h/4, where d = diameter = 1.0 m, h = 2.0 m.

v = 3.14(1)²×2/4

v = 1.57 m³ also,  ρ =  6712.03 kg/m³.

Substituting into equation 3

m = 1.57×6712.03

m = 10537.887 kg

m ≈ 10538 kg.

Thus the mass of the liquid = 10538 kg

3 0
3 years ago
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