Answer: 1.137*10^7 Btu/h.
Explanation:
Given data:
Efficiency of the plant = 4.5percent
Net power output of the plant = 150kw
Solution:
The required collection rate
QH = W/n
= 150/0.045 * 0.94782/ 1 /60 */60 Btu/h.
= 3333.333 *3412.152Btu/h.
= 11373840 Btu/h
= 1.137*10^7 Btu/h.
Answer:3.47 m
Explanation:
Given
Temperature(T)=300 K
velocity(v)=1.5 m/s
At 300 K


And reynold's number is given by



x=3.47 m
Answer:
the answer how you analyzs the problwm