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Scilla [17]
3 years ago
6

Why do the quadrants in coordinate plane go anti-clockwise?.

Engineering
1 answer:
tia_tia [17]3 years ago
7 0

Answer:

Quadrants are counter-clockwise because angles are measured counter-clockwise; and angles are measured counter-clockwise so that Cross Product of unit vector in X direction with that in the Y direction has to be the unit vector in the Z direction (coming towards us from the origin).

Explanation:

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1. Round off 2553 N to three significant figures.
Marizza181 [45]

Answer:

(1) 2553 N = 2550 N

(2) 58342 m = 58300 m

(3) 68.534 s = 68.5 s

Explanation:

To round off a number to any significant number start from the last digit, round it off to 1 if the number is up to 5 and to 0 if the last digit is less than 5. Add this 1 or 0 to the preceding digit and continue the process until you are left with three non zero digits, if you are rounding off to three significant figures.

(1) Round off 2553 N to three significant figures.

= 2550 N

(2) Round off 58342 m to three significant figures.

= 58300 m

(3) Round off 68.534 s to three significant figures.

= 68.500 s (zero after decimal point is insignificant)

= 68.5 s

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4 years ago
Imagine you are designing a new backpack. Which of the following statement(s) about
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The answer is D.) both A and C
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In a company, a new process is put in place that uses flash cards to make manufacturing more effective. What type of waste is th
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D. Workforce

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3 years ago
When you look at a drawing, how do you know if you are looking at US
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is it glizzy bread

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3 years ago
Q1. (20 marks) Entropy Analysis of the heat engine: consider a 35% efficient heat engine operating between a large, high- temper
Anvisha [2.4K]

The rate of gain for the high reservoir would be 780 kj/s.

A. η = 35%

\frac{w}{Q1} = \frac{35}{100}

W = 1.2*\frac{35}{100}*1000kj/s

W = 420 kj/s

Q2 = Q1-W

= 1200-420

= 780 kJ/S

<h3>What is the workdone by this engine?</h3>

B. W = 420 kj/s

= 420x1000 w

= 4.2x10⁵W

The work done is 4.2x10⁵W

c. 780/308 - 1200/1000

= 2.532 - 1.2

= 1.332kj

The total enthropy gain is 1.332kj

D. Q1 = 1200

T1 = 1000

\frac{1200}{1000} =\frac{Q2}{308} \\\\Q2 = 369.6 KJ

<h3>Cournot efficiency = W/Q1</h3>

= 1200 - 369.6/1200

= 69.2 percent

change in s is zero for the reversible heat engine.

Read more on enthropy here: brainly.com/question/6364271

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3 years ago
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