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3 years ago

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what is the total magnification of a microscope with an eyepiece magnification of 10x and an objective lens magnification of 50x

quizziz

1 answer:

Anon25 [30]3 years ago

8 0

Answer:

500x

Explanation:

A microscope had an eyepiece magnification of 10x

The objective lens magnification is 50x

Therefore the total magnification can be calculated as follows

= 10 × 50

= 500x

Hence the total Magnificattion is 500x

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An electron is accelerated by a 5.9 kV potential difference. das (sd38882) – Homework #9 – yu – (44120) 3 The charge on an elect

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Complete Question

An electron is accelerated by a 5.9 kV potential difference. das (sd38882) – Homework #9 – yu – (44120) 3 The charge on an electron is 1.60218 × 10−19 C and its mass is 9.10939 × 10−31 kg. How strong a magnetic field must be experienced by the electron if its path is a circle of radius 5.4 cm?

Answer:

The magnetic field strength is $B= 0.0048 T$

Explanation:

The work done by the potential difference on the electron is related to the kinetic energy of the electron by this mathematical expression

$\Delta V q = \frac{1}{2}mv^2$

Making v the subject

$v = \sqrt{[\frac{2 \Delta V * q }{m}] }$

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v is the velocity of electron

q charge on electron

$\Delta V$ is the potential difference

Substituting values

$v = \sqrt{\frac{2 * 5.9 *10^3 * 1.60218*10^{-19} }{9.10939 *10^{-31]} }$ f

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making B the subject

$B = \frac{mv}{rq}$

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Answer:

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