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zlopas [31]
3 years ago
8

2Al+3Cl2⟶2AlCl3

Chemistry
1 answer:
Leviafan [203]3 years ago
8 0

Answer:

7.335 moles of  Cl₂ are required to react with 4.89 miles of Al.

Explanation:

Given data:

Moles of Al = 4.89 mol

Number of moles of Cl₂ required = ?

Solution:

Chemical equation:

2Al + 3Cl₂    →   2AlCl₃

Now we will compare the moles of Al and chlorine from balance chemical equation.

                            Al           :         Cl₂

                             2           :           3

                            4.89      :         3/2×4.89 =7.335 mol

Thus, 7.335 moles of  Cl₂ are required to react with 4.89 miles of Al.        

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