A 10-kg block A is released from rest 2 m above the 5-kg plate P, which can slide freely along the smooth vertical guides BC and
DE. Determine the velocity of the block and plate just after impact. The coefficient of restitution between the block and the plate is e = 0.75. Also, find the maximum compression of the spring due to impact.The spring has an unstretched length of 600 mm
The spring with the 5 kg plate are stationary before impact at 450mm. The 600mm unstretch length of the spring is without the 5 kg plate
The spring with the 5 kg plate are stationary before impact at 450mm. The 600mm unstretch length of the spring is without the 5 kg plate
1 answer:
Answer:
Check the explanation
Explanation:
<u>Given data </u>
Mass of the block A is Ma = 10kg
Mass of the plate is Mp = 5kg
Coefficient of restitution between the block and that of the plate is e=0.75
Unstretched length of the spring is 0.6m
From the conservation of energy, we have four motion of block A from (1) to (2)
Then accordingly, we will have the step by step calculation in the attached image below .
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Answer:
The volume percentage of graphite is 10.197 per cent.
Explanation:
The volume percent of graphite is the ratio of the volume occupied by the graphite phase to the volume occupied by the graphite and ferrite phases. The weight percent in the cast iron is 3.2 wt% (graphite) and 96.8 wt% (ferrite). The volume percentage of graphite is:
Where:
- Volume occupied by the graphite phase, measured in cubic centimeters.
- Volume occupied by the graphite phase, measured in cubic centimeters.
The expression is expanded by using the definition of density and subsequently simplified:
Where:
,
- Masses of the ferrite and graphite phases, measured in grams.
- Densities of the ferrite and graphite phases, measured in grams per cubic centimeter.
If ,
,
and
, the volume percentage of graphite is:
The volume percentage of graphite is 10.197 per cent.
