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larisa [96]
4 years ago
15

A high-voltage direct-current (dc) transmission line between Celilo, Oregon and Sylmar, California is 845 mi in length. The line

contains four conductors, each weighing 2460 lbper 1000 ft.How many kilograms of conductor are in the line?
Engineering
1 answer:
Gennadij [26K]4 years ago
4 0

Answer:

<u>Total Mass of Conductors = 19913661.3 kg</u>

Explanation:

The total length is given as:

Total Length = 845 mi

Converting it to ft:

Total length = (845 mi)(5280 ft/1 mi)

Total length = 4,461,600 ft

The weight of one conductor per unit length is:

Mass of one conductor per unit length = 2460 lb/1000 ft

Mass of one conductor per unit length = 2.46 lb/ft

Since there are 4 conductors, therefore, total weight of all conductors per unit length will be:

Mass of all four conductors per unit length = 4 x 2.46 lb/ft

Mass of all four conductors per unit length = (9.84 lb/ft)(0.453592 kg/1 lb)

Mass of all four conductors per unit length = 4.463 kg/ft

Therefore, total mass of conductors in the line will be:

Total Mass of Conductors = (Mass of all four conductors per unit length)(Total Length)

Total Mass of Conductors = (4.463 kg/ft)(4,461,600 ft)

<u>Total Mass of Conductors = 19913661.3 kg</u>

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bazaltina [42]

Answer:

The following are the answer to this question:

Explanation:

In point a, Calculating the are of flow:

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In point b, Calculating the wetter perimeter.

\bold{P_w =B+2\times D_f}

      = 6 +2\times (5)\\\\= 6 +10 \\\\=16 \ ft

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\bold{R=\frac{A}{P_w}}

   =\frac{30}{16}\\\\= 1.875 \ ft

In point d, Calculating the value of Reynolds's number.

\bold{Re =\frac{4VR}{v}}

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     =750,000 V

Calculating the velocity:

V= \sqrt{\frac{8gRS}{f}}

   = \sqrt{\frac{8\times 32.2 \times 1.875 \times 0.02}{f}}\\\\=\frac{3.108}{\sqrt{f}}\\\\

\sqrt{f}=\frac{3.108}{V}\\\\

calculating the Cole-brook-White value:

\frac{1}{\sqrt{f}}= -2 \log (\frac{K}{12 R} +\frac{2.51}{R_e \sqrt{f}})\\\\ \frac{1}{\frac{3.108}{V}}= -2 \log (\frac{2 \times 10^{-2}}{12 \times 1.875} +\frac{2.51}{750,000V\sqrt{f}})\\

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3 years ago
A tailgate may have a latch on both sides.<br> O True<br> O False
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Answer:

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Explanation:

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3 years ago
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Answer:

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e.Yes

Explanation:

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The  probabilities  are computed using the EXCEL .

a) The required probability here is:

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=0.0199

Therefore the probability is 0.0199 .

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d) The required probability here is computed as:

P(10 less or equal to X less or equal to 20 ) = P(X less or equal to 19) - P(X less or equal to 10)

= binom.dist(19,500,0.05,TRUE) - binom.dist(10,500,0.05,TRUE)

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Answer:

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Explanation:

Previous concepts

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H_o =r x mv=rxL

Applying Newton’s second law to the right hand side of the above equation, we have that r ×ma = r ×F =

MO, where MO is the moment of the force F about point O. The equation expressing the rate of change  of angular momentum is this one:

MO = H˙ O

Principle of Angular Impulse and Momentum

The equation MO = H˙ O gives us the instantaneous relation between the moment and the time rate of change of angular  momentum. Imagine now that the force considered acts on a particle between time t1 and time t2. The equation MO = H˙ O can then be integrated in time to obtain this:

\int_{t_1}^{t_2}M_O dt = \int_{t_1}^{t_2}H_O dt=H_0t2 -H_0t1

Solution to the problem

For this case we can use the principle of angular impulse and momentum that states "The mass moment of inertia of a gear about its mass center is I_o =mK^2_o =30kg(0.125m)^2 =0.46875 kgm^2".

If we analyze the staritning point we see that the initial velocity can be founded like this:

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\omega =\frac{24}{1.14375}=20.983\frac{rad}{s}

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