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larisa [96]
3 years ago
15

A high-voltage direct-current (dc) transmission line between Celilo, Oregon and Sylmar, California is 845 mi in length. The line

contains four conductors, each weighing 2460 lbper 1000 ft.How many kilograms of conductor are in the line?
Engineering
1 answer:
Gennadij [26K]3 years ago
4 0

Answer:

<u>Total Mass of Conductors = 19913661.3 kg</u>

Explanation:

The total length is given as:

Total Length = 845 mi

Converting it to ft:

Total length = (845 mi)(5280 ft/1 mi)

Total length = 4,461,600 ft

The weight of one conductor per unit length is:

Mass of one conductor per unit length = 2460 lb/1000 ft

Mass of one conductor per unit length = 2.46 lb/ft

Since there are 4 conductors, therefore, total weight of all conductors per unit length will be:

Mass of all four conductors per unit length = 4 x 2.46 lb/ft

Mass of all four conductors per unit length = (9.84 lb/ft)(0.453592 kg/1 lb)

Mass of all four conductors per unit length = 4.463 kg/ft

Therefore, total mass of conductors in the line will be:

Total Mass of Conductors = (Mass of all four conductors per unit length)(Total Length)

Total Mass of Conductors = (4.463 kg/ft)(4,461,600 ft)

<u>Total Mass of Conductors = 19913661.3 kg</u>

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Answer:

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3 years ago
There are two types of cellular phones, handheld phones (H) that you carry and mobile phones (M) that are mounted in vehicles. P
nexus9112 [7]

Answer:

A) P(W) = 0.5

B) P(MF) = 0.3

C) P(H) = 0.6

Explanation:

We are told that there are two types of cellular phones which are handheld phones (H) that you carry and mobile phones (M) that are mounted in vehicles.

Also, Phone calls can be classified by the traveling speed of the user as fast (F) or slow (W).

Thus, the sample space is combination of types and classification we are given and it is written as;

S = {HF, HW, MF, MW}

A) Now, phones can either be fast(F) or slow(W). Thus, we can write;

P(F) + P(W) = 1

We are given P(F) = 0.5

Thus;

0.5 + P(W) = 1

P(W) = 1 - 0.5

P(W) = 0.5

B) Now, from the problem statement, a phone call can either be made with a handheld(H) or mobile(M). Thus the sample space partition is {H, M} and we can express as;

P(H ∩ F) + P(M ∩ F) = P(F)

We are given P[F] = 0.5 and P[HF] = 0.2.

P(H ∩ F) is same as P[HF]

Also, P(M ∩ F) is same as P(MF)

Thus;

0.2 + P(MF) = 0.5

P(MF) = 0.5 - 0.2

P(MF) = 0.3

C) Similarly, mobile Phone calls can either be fast or slow. It means the sample space partition is {F, W}

Thus;

P(M) = P(MW) + P(MF)

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Now, since cellular phones can either be handheld(H) or Mobile(M), then we can say;

P(H) + P(M) = 1

P(H) + 0.4 = 1

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3 years ago
The way most recursive functions are written, they seem to be circular at first glance, defining the solution of a problem in te
EastWind [94]

Question Continuation

int factorial(int n) {

if(n == 0)

return 1;

else

return n * factorial(n - 1);

}

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Answer:

1. Brief explanation why this recursive function works.

First, the recursive method factorial is defined.

This is the means through with the machine identifies the method.

The method is defined as integer, the machine will regard it as integer.

When the factorial is called from anywhere that has access to it, which in this case is within the factorial class itself. This means you can call it from the main method, or you can call it from the factorial method itself. It's just a function call that, well, happens to call itself.

2. Steps to calculate factorial(3)

1 First, 3 is assigned to n.

2. At line 2, the machine checks if n equals 0

3. If yes, the machine prints 1

4. Else; it does the following from bottom to top

factorial(3):

return 3*factorial(2);

return 2*factorial(1):

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Answer:

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<em>b) Dead Zones :</em>

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3. Last but not the least, if you increase the concentration of ammonia nitrogen, the dissolved oxygen rate will be decreased and it has a inverse relation which is very dangerous to marine life underwater.

<em>d) Streeter-Phelps DO curve:</em>

Please refer to the attachment, I have attached the curve.

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It can be further studied from the curve that, how much loss sewage and other pollutants can endure upon the marine life.

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Explanation:

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