Answer:
The answer to your question is: more less
Explanation:
I suggest you these answers:
a) PCl₅ (s) ⇒ PCl₃ (s) + Cl₂ (g)
b) ZnBr₂ (aq) + Li₃CO₃ (aq) ⇒ ZnCO₃ (s) + LiBr (aq)
c) C₂H₄ + O₂ ⇒ CO₂ (g) + H₂O (l)
Do you have to balance them?
This picture represents electrons
Answer:
18.7887 g of NaCl
Explanation:
<em>The question reads - How many grams of NaCl will be produced from 18.0 g of Na and 23.0 g of Cl2?</em>
Let us start by writing out the balanced equation of the reaction:
Na + Cl2 ---> NaCl2
1 mole, each of Na and Cl2 is required to produce 1 mole of NaCl.
mole = mass/molar mass
Therefore
18 g of Na = 18/23 = 0.7826 mole
23 g of Cl2 = 23/71 = 0.3239 mole
In this case, the Na is in excess and the Cl2 becomes the limiting reagent. Hence
0.3239 mole of Cl2 will react with 0.3239 mole of Na to yield 0.3239 mole of NaCl.
mass of 0.3239 mole NaCl = 0.3239 x 58 = 18.7887 g
<u>Hence, 18.7887 grams of NaCl will be produced from 18.0 g of Na and 23.0 g of Cl2.</u>
No, pure cocoa powder is not very soluble. A hot cocoa mix will dissolve well under warm temperatures.
Answer:
168.0 g
Explanation:
First thing, write a balanced chemical equation:
n(H2SO4) = concentration * volume
= 1.0 M * 2.0 L
= 2.0 mol
According to the balanced equation, 1 mol of acid requires 2 mol of sodium bicarbonate. This means that 2 mol of acid requires 2 mol of sodium bicarbonate. What mass of sodium bicarbonate is this?
mass (NaHCO3) = number of moles * molar mass
= 2.0 mol * 84.0065 g/mol
= 168.0 g
