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worty [1.4K]
3 years ago
8

I need the answer for this

Chemistry
1 answer:
viva [34]3 years ago
5 0

Answer:

need points

Explanation:

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Jude has a mutation in the gene that codes for a certain digestive enzyme. However, these enzymes function normally.
Molodets [167]

Answer:

b

Explanation:

6 0
3 years ago
If the freezing point of a soda is – 4.5 ºC and you leave it in your car overnight when the temperature dips to 25 ºF, will the
Sveta_85 [38]

Explanation:

We leave a soda in the car overnight and the temperature dips to 25 °F. To see if it will freeze we have to convert the °F to °C.

T(°C) = ( T(°F) - 32 ) *5/9

T(°C) = (25 - 32) *5/9

T(°C) = -3.9 °C

Since -3.9 °C is a temperature greater than the freezing point (-4.5 °C) the soda won't freeze.

Answer: The soda won't freeze.

6 0
2 years ago
1. A weather balloon is filled with helium on a cool morning when the temperature is 13.0°C. The temperature is predicted to rea
azamat

Answer:

Number of moles: n = 1.29 moles

If the temperature reaches 35°C which is 308.15 K the balloon will burst

Explanation:

Using the formula: PV = nRT  

Where P is pressure in atm, V is volume in L, n is the number of moles, R is the gas constant which can be 8.314 J/mol K or 0.08206 atm L/mol K, and T is temperature in K.

In order to know which R to use, just take a look at the units. If you are given the pressure in atm, then use 0.08206 atm L/mol K. If you are given energy in Joules instead, then use 8.314 J/mol K.

Problem solution:

1 atm = 101.325 kPa, so 238 kPa is equal to 2.349 atm

1°C is 274.15 K, so 13°C is 286.15 k

Using the formula PV = nRT

2.349 atm * 12.9 L = n * 0.08206 atm L/mol K * 286.15 k  

n = (30.302 atm L) / (23.481 atm L/mol)

n = 1.29 moles

If the temperature reaches 35°C which is 308.15 K the balloon will burst:

P = nRT/V

P = (1.29 moles * 0.08206 atm L/mol K * 308.15 k) / 12.9 L

P = 2.529 atm = 256.21 kPa

4 0
3 years ago
if you have a solution that contains 46.85 g of codeine, C18H21NO3, in 125.5 g of ethanol, C2H5OH, what is the mole fraction of
OverLord2011 [107]

Answer:

The mole fraction of codeine is 5.4%

Explanation:

Mole fraction = Mole of solute / Total moles (Mole solute + Mole solvent)

Solute (Codeine)

Molar mass 299.36 g/m

Mass / Molar mass = Mole →  46.85 g /299.36 g/m = 0.156 moles

Solvent (Ethanol)

Molar mass 46.07 g/m

125.5 g / 46.07 g/m = 2.724 moles

Mole fraction (Codeine) 0.156 / (0.156 + 2.724) → 0.054

3 0
3 years ago
Name the following compounds:
ankoles [38]
A) cesium chloride
B) barium oxide
C) potassium sulfide
D) beryllium chloride
E) hydrogen bromide
F) aluminum fluoride
3 0
3 years ago
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