You would calculate them by dividing them and then multiplying to get the final answer
Answer:
Explanation:
1)
H₂SO₄:
Element (symbol) No of atoms in No of compounds Total atoms
1 molecule coefficient
H 2 1 2
S 1 1
O 4 4
2)
2H₃PO₄:
Element (symbol) No of atoms in No of compounds Total atoms
1 molecule coefficient
H 3 2 6
P 1 2
O 4 8
There are two mole of H₃PO₄. One mole contain 3 hydrogen atom, 1 phosphorus atom and 4 oxygen atoms. Thus in two mole of compound 6 hydrogen atoms, 2 phosphorus atom and 8 oxygen atoms are present.
A and d is physical, b and c is chemical
Answer:
d. 12.3 grams of Al2O3
Explanation:
The balanced chemical equation of this chemical reaction is as follows:
4Al + 3O2 --> 2Al2O3
Based on the balanced equation, 4 moles of aluminum (limiting reagent) reacts to form 2 moles of aluminum oxide (Al2O3).
First, we need to convert the mass of aluminum to moles using the formula;
mole = mass/molar mass
Molar mass of Al = 27g/mol
mole = 6.50/27
= 0.241mol of Al.
Hence, if 4 moles of aluminum (limiting reagent) reacts to form 2 moles of aluminum oxide (Al2O3).
Then, 0.241mol of Al will produce (0.241 × 2/4) = 0.241/2 = 0.121mol of Al2O3.
Convert this mole value to molar mass using mole = mass/molar mass
Molar mass of Al2O3 = 27(2) + 16(3)
= 54 + 48
= 102g/mol
mass = molar mass × mole
mass = 102 × 0.121
mass of Al2O3 = 12.34grams.
Actually the total abundance of the isotopes of any
element in this world must sum up to 100%. So we initially know that 12 C is
98.9 percent abundant, therefore the remaining of the 100 percent must be of 13
C, that is:
13 C = 100% - 98.9%
<span>13 C = 1.1% </span>
