3 years ago

ASAP! What numbers makes this equation true?

Mathematics

2 answers:

Korvikt [17]3 years ago

7 0

x = 5 The answer is c

SOVA2 [1]3 years ago

5 0

Answer:

C. 5

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if x-1 is a factor of P(x)=x^3- 5x^2 + 7x-3 which of the following represents the complete factorization for P(x)?

kozerog [31]

Answer:

P(x) = (x-1)² (x-3)

Step-by-step explanation:

P(x)=x³- 5x² + 7x-3 = x² (x-1) - 4x(x-1) + 3(x-1) = (x²-4x+3)(x-1)

P(x) = (x-1)(x-3)(x-1) = (x-1)² (x-3)

3 0

4 years ago

From greatest to least?? 1.11,0.111,1.01,1.001

vodomira [7]

0.111, 1.001, 1.001, 1.11

hope this helps

7 0

3 years ago

Read 2 more answers

How do I solve

Maslowich

$Use:\\\\(ab)^n=a^nb^n\\\\(a^n)^m=a^{nm}\\\\a^n\cdot a^m=a^{n+m}\\\\\sqrt[n]{a}=a^\frac{1}{n}\\------------------------\\\\\left(16n^4\right)^{\frac{5}{4}}=16^\frac{5}{4}\left(n^4\right)^\frac{5}{4}=16^{1\frac{1}{4}}n^{4\cdot\frac{5}{4}}=16^{1+\frac{1}{4}}n^5=16^1\cdot16^\frac{1}{4}\cdot n^5\\\\=16\cdot\sqrt[4]{16}\cdot n^5=16\cdot2\cdot n^5=\boxed{32n^5}\\\\\sqrt[4]{16}=2\ because\ 2^4=16\\\\\text{Answer}\ \boxed{\left(16n^4\right)^\frac{5}{4}=32n^5}$