1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
jenyasd209 [6]
3 years ago
13

A projectile fired into the air, explodes, and splits into two halves of equal mass that hit the ground at the same time. If the

projectile had not exploded, it would have landed at point X, which is a distance R to the right of the launch point. After the explosion, one of the halves lands at point Y, which is a distance 2R to the right of the launch point. If air resistance is negligible, where did the other half land
Physics
1 answer:
steposvetlana [31]3 years ago
4 0

Answer:

At the Launch point

Explanation:

We are told that after the explosion, one of the halves landed at the point Y, which is a distance of 2R to the right side of the launch point.

This means that the only way one half of the object would have gone double the original distance of R is if it's velocity was two times that of the initial velocity. Furthermore, the only way that will make sense is if the other half fell straight down. So In conclusion, if air resistance is neglected, the other half will land at the initial velocity point which is at launch point.

You might be interested in
How do scientists use the doppler effect to understand the universe?
Nadusha1986 [10]

For the First answer, It would be "A"

The for the next one the answer is "C"

I hope this helps. :)

6 0
3 years ago
Read 2 more answers
A team of engineering students is testing their newly designed 200 kg raft in the pool where the diving team practices. The raft
elena-s [515]

Answer:

The water level rises more when the cube is located above the raft before submerging.

Explanation:

These kinds of problems are based on the principle of Archimedes, who says that by immersing a body in a volume of water, the initial water level will be increased, raising the water level. That is, the height in the container with water will rise in level. The difference between the new volume and the initial volume of the water will be the volume of the submerged body.

Now we have two moments when the steel cube is held by the raft and when it is at the bottom of the pool.

When the cube is at the bottom of the water we know that the volume will increase, and we can calculate this volume using the volume of the cube.

Vc = 0.45*0.45*0.45 = 0.0911 [m^3]

Now when a body floats it is because a balance is established in the densities, the density of the body and the density of the water.

Ro_{H2O}=R_{c+r}\\where:\\Ro_{H2O}= water density = 1000 [kg/m^3]\\Ro_{c+r}= combined density cube + raft [kg/m^3]

Density is given by:

Ro = m/V

where:

m= mass [kg]

V = volume [m^3]

The buoyancy force can be calculated using the following equation:

F_{B}=W=Ro_{H20}*g*Vs\\W = (200+730)*9.81\\W=9123.3[N]\\\\9123=1000*9.81*Vs\\Vs = 0.93 [m^3]

Vs > Vc, What it means is that the combined volume of the raft and the cube is greater than that of the cube at the bottom of the pool. Therefore the water level rises more when the cube is located above the raft before submerging.

7 0
4 years ago
Which event is an example of melting?
qaws [65]

Answer:

welding metal

Explanation:

5 0
3 years ago
Water at room temperature is discharged from a pipe at a rate of 1000 gallons per minute (gpm). Express this flow rate in cubic
marshall27 [118]

Answer

given,

discharge rate from pipe = 1000 gallons/minutes

now,

flow rate in  cubic meters per second

1 gallon = 0.00378541 m³

1 min = 60 s

Q = 1000\times \dfrac{0.00378541\ m^3}{1\ gallon}\times \dfrac{1\ min}{60\ s}

Q = 0.063 m³/s

flow rate in  liters per minute

1 gallon = 3.78541 L

 Q = 1000\times \dfrac{3.78541\ m^3}{1\ gallon}

 Q = 3785.41 m³/min

flow rate in cubic feet per second

 1 gallon = 0.133681 ft³

 1 min = 60 s

Q = 1000\times \dfrac{0.133681\ ft^3}{1\ gallon}\times \dfrac{1\ min}{60\ s}

Q = 2.23 ft³/s

4 0
3 years ago
Can y'all please help me out with this ?
Inessa05 [86]

Answer:

no where is the main part of the question dude

3 0
3 years ago
Other questions:
  • (a) Calculate the magnitude of the gravitational force exerted by Mars on a 67 kg human standing on the surface of Mars. (The ma
    8·1 answer
  • F = ma solve for m .......
    11·2 answers
  • A roller coaster car starts at a height of 90 M at Point a and is moving at a speed of 20 m per second on a later Hill at Point
    12·2 answers
  • Which of the following is the equation for impulse
    13·1 answer
  • a car has a mass of 1.00 x 10^3 kilograms and it has an acceleration of 4.5 meters/second what is the net force on the car
    6·2 answers
  • A satellite moves in a circular earth orbit that has a radius of 7.49 x 106 m. A model airplane is flying on a 24.1-m guideline
    15·1 answer
  • An archer pulls the bowstring back for a distance of 0.470 m before releasing the arrow. The bow and string act like a spring wh
    15·1 answer
  • Solve 3x+1<br><img src="https://tex.z-dn.net/?f=%20%5Cleqslant%201" id="TexFormula1" title=" \leqslant 1" alt=" \leqslant 1" ali
    15·1 answer
  • WILL GIVE BRAINLIEST! QUICK PLEASE HELP!!!
    8·1 answer
  • Explain why aircraft are carefully designed so that parts do not resonate.
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!