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jenyasd209 [6]
3 years ago
13

A projectile fired into the air, explodes, and splits into two halves of equal mass that hit the ground at the same time. If the

projectile had not exploded, it would have landed at point X, which is a distance R to the right of the launch point. After the explosion, one of the halves lands at point Y, which is a distance 2R to the right of the launch point. If air resistance is negligible, where did the other half land
Physics
1 answer:
steposvetlana [31]3 years ago
4 0

Answer:

At the Launch point

Explanation:

We are told that after the explosion, one of the halves landed at the point Y, which is a distance of 2R to the right side of the launch point.

This means that the only way one half of the object would have gone double the original distance of R is if it's velocity was two times that of the initial velocity. Furthermore, the only way that will make sense is if the other half fell straight down. So In conclusion, if air resistance is neglected, the other half will land at the initial velocity point which is at launch point.

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The change in heat q for the aluminum cup is 141 J.  

<h3>What is Specific heat?</h3>

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The answer's sign dig is determined by a calculation's lowest sign digits.

The solution will need 3 digits because the temperatures are provided with 3 significant digits and the specified heat has 3 significant digits (the mass has 4 significant digits).

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3 years ago
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Who has greater displacement, an astronaut who has just completed an orbit of the earth or you when you have just traveled from
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Answer:

Explanation:

This is going to sound like an absurd answer, but sometimes physics can be a little strange.

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So the answer is you have the greater displacement when you walked one way to school.  The starting point and the ending point are different. You have gone further.

However just to make things a little nasty, when you walk home again, your displacement will be the same as the astronaut's -- 0 meters because you will be right back where you started from.

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If measurements if a gas are 75L and 300 full-scale and then the gas is measured a second time and found to be 50L, describe wha
swat32
The answer is a bit confusing, so I did some research and fount the original question. This is the complete question:

"<span>If measurements of a gas are 75L and 300 kilopascals and then the gas is measured a second time and found to be 50L, describe what had to happen to the pressure (if temperature remained constant). Include which law supports this observation".

From that:

1) Data:

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Boyle's law states that the volume of a fixed amount of gas, at constant temperarature, is inversely related with the pressure.

In mathematical form that statement becomes into this equation:

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Answer: following Boyle's law, when the gas passed from 75 liter to 50 liter the pressure had to increase from 300 kPa to 450 kPa.

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