Answer:
His kinetic energy when he runs at that 5 m/s is 750 joules
Explanation:
The given information are;
The mass of, Lance, the runner = 60-kg
The speed by which Lance is running = 5 m/s
The kinetic energy, KE, is given by the relation;
KE = 1/2×m×v²
Where;
m = The mass = 60-kg
v = The instantaneous speed of motion = 5 m/s
The kinetic energy can be found by substituting the values of the variables in the kinetic energy equation as follows;
KE = 1/2 × 60 kg × (5 m/s)² = 750 joules
His kinetic energy when he runs at that 5 m/s is 750 joules.
Answer: -
12.41 g
Explanation: -
Mass of CO₂ = 42 g
Molar mass of CO₂ = 12 x 1 + 16 x 2 = 44 g / mol
Number of moles of CO₂ = 
= 0.9545 mol
The balanced chemical equation for this process is
2C₆H₆ + 15O₂ → 12CO₂ + 6H₂O
From the balanced chemical equation we see
12 mol of CO₂ is produced from 2 mol of C₆H₆
0.9545 mol of CO₂ is produced from 
= 0.159 mol of C₆H₆
Molar mass of C₆H₆ = 12 x 6 + 1 x 6 =78 g /mol
Mass of C₆H₆ =Molar mass x Number of moles
= 78 g / mol x 0.159 mol
= 12.41 g
Answer:
We can see that at the boiling point, both liquid and gas are in equilibrium with one another. This is true for any applied pressure and boiling point temperature combination. As a result, we see liquid-gas equilibrium for every temperature and pressure combination on the graph in Figure 13.6.
Answer:
A mole is the amount (10) of material containing 6.02214 × 10 raised to the power of 23 particles.
The two factors that are mainly responsible for determining the thermal energy of a substance are Temperature and Mass.
<h3><u>Explanation:
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Thermal energy is the total energy of the substance.
Temperature: The temperature and thermal energy of a substance are directly related to each other(direct proportion) which means that the greater the temperature, the greater will be the thermal energy of that particular substance.
Mass: Consider a situation, if we have two or more substances that have the same temperature the substance with the highest mass will have the most thermal energy than the others.
