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fiasKO [112]
3 years ago
11

use the equation below to determine how many liters of NH3 are needed to react completely with 10.0 L of N0 at STP

Chemistry
1 answer:
kupik [55]3 years ago
3 0

Answer is: 6.66 L of NH3 are needed to react completely.

Balanced chemical equation: 4NH₃ + 6NO  → 5N₂ + 6H₂O.

V(NO) = 10.0 L; volume of nitrogen(II) oxide.

V(NH₃) = ?

Vm = 22.4 L/mol; molar volume at STP.

n(NO) = V(NO) ÷ Vm.

n(NO) = 10 L  ÷ 22.4 L/mol.

n(NO) = 0.446 mol; amount of nitrogen(II) oxide.

From balanced chemical equation: n(NO) : n(NH₃) = 6 : 4

0.446 mol : n(NH₃) = 6 : 4.

n(NH₃) = 0.3 mol; amount of ammonia.

V(NH₃) = 0.3 mol · 22.4 L/mol.

V(NH₃) = 6.66 L.

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When the following equation is balanced, what is the coefficient for NaNO3?
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<h3>Further explanation </h3>

Equalization of chemical reaction equations can be done using variables. Steps in equalizing the reaction equation:  

• 1. gives a coefficient on substances involved in the equation of reaction such as a, b, or c etc.  

• 2. make an equation based on the similarity of the number of atoms where the number of atoms = coefficient × index between reactant and product  

• 3. Select the coefficient of the substance with the most complex chemical formula equal to 1  

Reaction

AI(NO₃)₃ +Na₂SO₄ → Al₂(SO₄) + NaNO₃

give coefficient

aAI(NO₃)₃ +bNa₂SO₄ → Al₂(SO₄)₃ +c NaNO₃

Al, left=a, right=2⇒a=2

N, left=3a, right=c⇒3a=c⇒3.2=c⇒c=6

Na, left=2b, right=c⇒2b=c⇒2b=6⇒b=3

The equation becomes :

2AI(NO₃)₃ +3Na₂SO₄ → Al₂(SO₄)₃ +6NaNO₃

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