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Archy [21]
2 years ago
15

A chemist dissolves 249.mg of pure perchloric acid in enough water to make up 380.mL of solution. Calculate the pH of the soluti

on. Be sure your answer has the correct number of significant digits.
Chemistry
1 answer:
Alla [95]2 years ago
4 0

Answer:

pH = 2.18

Explanation:

Perchloric acid (HClO₄) is a strong acid. This means that in an aqueous solution it completely dissociates into H⁺ and ClO₄⁻ species.

First we <u>convert 249 mg HClO₄ into moles</u>, using its <em>molecular weight</em>:

  • 249 mg HClO₄ ÷ 100.46 mg/mmol = 2.49 mmol HClO₄

<em>Because it is a strong acid</em>, 2.49 mmol HClO₄ = 2.49 mmol H⁺

We <u>calculate the molar concentration of H⁺</u>:

  • 2.49 mmol H⁺ / 380 mL = 6.52x10⁻³ M

Finally we <u>calculate the pH of the solution</u>:

  • pH = -log[H⁺] = -log(6.52x10⁻³)
  • pH = 2.18

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What is the identity of the element, and how many neutrons does it have? An elements most stable ion forms an ionic compound wit
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B. CA, 14

Explanation:

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6 0
3 years ago
In the following equation,
Nina [5.8K]
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3 0
3 years ago
ammonia (NH3(g) Hf=-45.9 kJ/mol) reacts. with oxygen to produce nitrogen and water (H2O(g) Hf = -241.8 kJ/mol according to the e
kherson [118]

Answer:

ΔH°_rxn = -195.9 kJ·mol⁻¹

Explanation:

                              4NH₃(g) + 3O₂(g) ⟶ 2N₂(g) +6H₂O(g)

ΔH°_f/(kJ·mol⁻¹):    -45.9          0                 0        -241.8

The formula relating ΔH°_rxn and enthalpies of formation (ΔH°_f) is

ΔH°_rxn = ΣΔH°_f(products) – ΣΔH°_f(reactants)

ΣΔH°_f(products) = -6(241.8) = -1450.8 kJ

ΣΔH°_f(reactants) = -4(45.9) = -183.6 kJ

ΔH°_rxn =  (-1450.8 + 183.6) kJ = -1267.2 kJ

6 0
3 years ago
Read 2 more answers
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