The laboratory procedure that best illustrate the law of conservation is
heating 100 g of CaCo3 to produce 56 g of CaO (answer C)
<u><em>explanation</em></u>
According to the law of mass conservation , the mass of the reactant must be equal to the mass of the product.
According to option c Heating 100 g CaCO3 to produces 56 g CaO ( 40 +16=56)
The remaining mass = 100-56 = 44 which would the mass of CO2 [ 12 + (16 x2)]= 44 since CaCO3 decomposes to produce CaO and CO2
Therefore the mass of reactant= 100g
mass of product = 56 g +44 g =100
Therefore the laboratory procedure for decomposition of CaCO<em>3</em> illustrate the law of mass conservation since the mass of reactant = mass of product.
Answer: The pressure in the can is 4.0 atm
Explanation:
According to ideal gas equation:
P = pressure of gas = ?
V = Volume of gas = 0.410 L
n = number of moles = 
R = gas constant =
T =temperature =
Thus the pressure in the can is 4.0 atm
