Answer:
79.9 amu
Explanation:
Given data:
Atomic mass of bromine = ?
Percent abundance of 1st isotope = 50.7%
Atomic mass of 1st isotope = 78.92 amu
Percent abundance of 2nd isotope = 49.3%
Atomic mass of 2nd isotope =80.92 amu
Solution:
Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) / 100
Average atomic mass = (50.7×78.92)+(49.3×80.92) /100
Average atomic mass = 4001.24 + 3989.36 / 100
Average atomic mass = 7990.6 / 100
Average atomic mass = 79.9 amu.
Answer: Compound are different than elements because compounds are combinations of 2 or more elements.
<u>Answer:</u> The volume of concentrated hydrochloric acid required is 16.53 mL
<u>Explanation:</u>
To calculate the volume of concentrated solution, we use the equation:
where,
are the molarity and volume of the concentrated solution
are the molarity and volume of diluted solution
We are given:
Conversion factor: 1 L = 1000 mL
Putting values in above equation, we get:
Hence, the volume of concentrated hydrochloric acid required is 16.53 mL
Answer:
I would put, A substance has two different parts of it, a pure substance and a compound and mixtures have two as well called, homogenous mixtures and hetrogeneous mixtures.
Explanation:
