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3 years ago

Find the nth term of this number sequence 1

Mathematics

2 answers:

raketka [301]3 years ago

3 0

Answer:

Step-by-step explanation:

hdgjjgggughggugfcghfxxgh

alekssr [168]3 years ago

3 0

The nth term in an arithmetic sequence is given by n = a + (n - 1) * d, where a is the first term in the sequence, and d is the common difference, given by the expression 2nd term - 1st term = 3rd term - 2nd term = nth term - (n - 1)th term.

So,

n = 1 + (n - 1) * (7 - 1)

n = 1 + (n - 1) * 6

n = 1 + 6n - 6

Take like terms,

n - 6n = 1 - 6

-5n = -5

n = 1,

So the nth term is equal to 1

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Komok [63]

Y because if you add them you will get 10x =-10
The y will be eliminated because you have positive 3 -4

6 0

3 years ago

Distributing property and combining like terms -10(1-3x)-10

ikadub [295]

Answer:

-20 + 30x

Step-by-step explanation:

-10(1) = -10

-10(-3x) = 30x

new equation

-10 + 30x -10

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-20 + 30x

7 0

3 years ago

Circle the value that is not equivalent to the other values 4.07 4.070 4.70 4.0700

cricket20 [7]

Answer:

4.70

Step-by-step explanation:

it is bigger then the other numbers

6 0

3 years ago

Solve for x. 5 10 12 13

zysi [14]

Answer: B) 4 & 1/6

Nice work on getting the correct answer.

============================================================

Explanation:

x is opposite the marked acute angle

5 is opposite the corresponding acute angle

So x and 5 are proportional to each other. We can form the ratio x/5

Similarly, 10 and 12 are proportional to one another. We can form the ratio 10/12.

Set those ratios equal to each other and solve for x

x/5 = 10/12

12x = 5*10 ... cross multiply

12x = 50

x = 50/12 ...... divide both sides by 12

x = (25*2)/(6*2)

x = 25/6

x = (24+1)/6

x = 24/6 + 1/6

x = 4 + 1/6

x = 4 & 1/6 which shows why choice B is the answer.

Side note: 25/6 = 4.167 approximately

8 0

3 years ago

Read 2 more answers

Four times the sum of three consecutive odd integers is seven hundred sixty-five less than three times the product of the larger

Andre45 [30]

Answer:

The consecutive odd integers are (15, 17, 19) or (-17, -15, -13).

Step-by-step explanation:

Let the three consecutive odd integers be: $x-2,x\ and \ x+2$

The condition given is:

$4[x-2+x+x+2]=3x(x+2)-765$

Solve this for x as follows:

$4[x-2+x+x+2]=3x(x+2)-765\\4\times 3x=3x^{2}+6x-765\\3x^{2}-6x-765=0\\x^{2}-2x-255=0\\x^{2}-17x+15x-255=0\\x(x-17)+15(x-17)=0\\(x-17)(x+15)=0$

If $(x-17)=0$ then the value of x is 17.

The odd numbers are:

$x-2=17-2=15\\x=17\\x+2=17+2=19$

If $(x+15)=0$ then the value of x is -15.

The odd numbers are:

$x-2=-15-2=-17\\x=-15\\x+2=-15+2=-13$

Thus, the consecutive odd integers are (15, 17, 19) or (-17, -15, -13).

7 0

3 years ago