Answer:
if you are required to find the equation of a straight line use the formula y-y1= m (x-x1)
y+2=-3(x-1)
y+2=-3x+3
y= -3x+3-2
y -3x+1
hope this helps
So the perimeter(P) of a rectangle would be:
P= 2L+2W
L being the length and W being the width.
The problem says the length is 4cm more than the width, so L= 4+W.
So if we substitute L with 4+W, we get:
P= 2(4+W) + 2W
Use the Distributive Property
P= 8+2W+2W
Combine like terms
P=8+4W
Since we're given the perimeter, we could replace P with 52. So:
52=8+4W
Subtract 8 to both sides
44=4W
Divide 4 to both sides
11=W
Therefore, the width is 11cm
And since the length is 4cm more than the width, we could add 4cm to 11cm to find that the length is 15cm
Thus, the dimensions of the rectangle are 15cm by 11cm
Answer:
C: y+7=2/5(x+4)
Step-by-step explanation:
The point-slope form of the equation of a line with slope m through point (h, k) is ...
y -k = m(x -h)
You are given m=2/5 and (h, k) = (-4, -7). Put these numbers into the form and simplify the signs:
y -(-7) = 2/5(x -(-4)) . . . . . numbers put into the form
y +7 = 2/5(x +4) . . . . . . . signs simplified . . . . matches choice C
Answer:
b
Step-by-step explanation:
count two up, and 5 to the right
