Answer:
65.75 deg
Explanation:
v = initial speed of launch of projectile
θ = initial angle of launch
H = maximum height of the projectile
maximum height of the projectile is given as
eq-1
D = horizontal range of the projectile
horizontal range of the projectile is given as
eq-2
It is also given that
D = 1.8 H
using eq-1 and eq-2
tanθ = 2.22
θ = 65.75 deg
Answer:
First of all the attack is gonna die because its 2020 who throws a rock up over a wall to kill someone(cavemen) and
it's gonna be ↓
explanation:
An attacker at the base of a castle wall 3.60 m high throws a rock straight up with speed 8.00 m/s from a height of 1.70 m above the ground.
(a) Will the rock reach the top of the wall?
(b) If so, what is its speed at the top? If not, what initial speed must it have to reach the top?
(c) Find the change in speed of a rock thrown straight down from the top of the wall at an initial speed of 8.00 m/s and moving between the same two points.
(d) Does the change in speed of the downward-moving rock agree with the magnitude of the speed change of the rock moving upward between the same elevations? Explain physically why it does or does not agree.
There are some mistakes in the question as units pressure and air density are not written correctly.The correct question is here
On a summer day in Narragansett, Rhode Island, the air temperature is 74°F and the barometric pressure is 14.5 lbf/in². Estimate the air density in kg/m³.
Answer:
p=1.175 kg/m³
Explanation:
Given data
Temperature =74 F
Barometric pressure=14.5 lbf/in²
To find
Air density
Solution
From ideal gas law
As mass/volume is pressure So
First we need to convert barometric pressure lbf/in² to N/m²
So
Now Substitute the given value and pressure to find air density