Question

On a circular racetrack with a radius of 3.23 m, a certain road car set a speed record of 3.72

Answer 1

Answer:

F = 1071.08 N

Explanation:

Given that,

The radius of the circular track, r = 3.23 m

Speed of the car, v = 3.72 m/s

The mass of the car, m = 250 kg

We need to find the net force acting on it. The centripetal force will act on it and it is given by the relation as follows :

$F=\dfrac{mv^2}{r}\\\\F=\dfrac{250\times (3.72)^2}{3.23}\\\\F=1071.08\ N$

So, the net force acting on the car is 1071.08 N.