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2 years ago

Gasoline has a density of 0.749 g/ml. how many pounds does 19.2 gallons of gasoline weigh?

2 answers:

6 0

A good first step is writing the amount in terms of ml.

19.2 gallons = 72.68 L = 72680 ml

that would mean it weighs 0.749*720680g = 54437.32ml = 54.437 L

hope that helps :)

7nadin3 [17]2 years ago

5 0

Answer;

mass will be; 119.76 lbs

solution and Explanation;

1,000 g = 2.2 lb and 1 gal = 3785.41 mL.

Density = 0.749 g/ml * 2.2 lb/1,000 g * 3785.41 mL/1 gal

Density = 6.2376 lb/gal

Mass = 6.2376 lb/gal*19.2 gal

Mass = 119.76 lbs

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Ammonia is a main ingredient in fertilizers. The following reaction is used to synthesize ammonia, NH3. How many liters of ammon

PolarNik [594]

According to Balance chemical equation,

N₂ + 3 H₂ → 2 NH₃

1 mole of Nitrogen reacts with 3 moles of Hydrogen to produce 2 mole of Ammonia.
It is known that i mole of any gas at standard temperature and pressure occupies 22.4 L of Volume. So, we can also say,

22.4 L (1 × 22.4) of Nitrogen gas (in question it is taken in excess) reacts with 67.2 L (22.4 × 3) of Hydrogen gas to produce 44.8 L (22.4 × 2) of Ammonia.

Result:
44.8 L is the correct answer.

8 0

2 years ago

This element is a liquid at room temperature. (A) Hg (B) Th (C) Na (D) Cl (E) Co

gulaghasi [49]

A) Hg, or Mercury, is a liquid at room temperature. Hope this helps!!

7 0

3 years ago

Read 2 more answers

Consider the reaction: Mg(OH)₂ (s) ⇌ Mg²⁺ (aq) + 2 OH⁻ (aq)

balandron [24]

The value of Kc for the equilibrium is 0.150 mole² / litre ²

Explanation:

Given:

An equilibrium mixture in an 1.00 L vessel contains 5.30 moles of

Mg(OH )₂ 0.800 moles of Mg²⁺ and 0.0010 moles OH₋

We have to find the value of Kc

Step 1: Find the equilibrium Concentration.
Step 2: Substitute the values in the equation.
Step 3: Find the value of Kc.
I have attached the document for the detailed explanation

The value of Kc for the equilibrium is 0.150 mole² / litre ²

Download pdf

8 0

3 years ago

Two liquids are analyzed and found to both be 85.7% carbon and 14.3% hydrogen. At 750 mmHg and 150 C, both are gases. At these c

vodomira [7]

Answer:

Molecular formula A: C₅H₁₀

Molecular formula B: C₇H₁₄

Explanation:

It is possible to obtain empirical formula of compounds using percent composition, thus:

C: 85.7% × (1mol / 12.01g) = 7.136 moles C

H: 14.3% × (1mol / 1.01g) = 14.158 moles H

Mole ratio of H:C is:

14.158mol / 7.136mol = 2

That means in compounds A and B you have 2 hydrogens per atom of carbon and empirical formila is:

CH₂

Using PV = nRT, moles of A and B are:

Where P is pressure (750mmHg / 760 = 0.987atm), V is volume (0.8000L), R is gas constant (0.082atmL/molK), and T is temperature (150°C +273.15 = 423.15K)

Moles A and B: n = PV / RT

n = 0.987atm×0.8000L / 0.082atmL/molK×423.15K

n = 0.0228 moles of A and B.

Using the mass of A and B it is possible to find molar mass of each compound:

A = 1.60g / 0.0228mol = 70.31g/mol

B = 2.22g / 0.0228mol = 97.56g/mol

As empirical formula of both compounds is CH₂, (molar mass = 14.03g/mol). Molecular formula of compounds is:

A = 70.31g/mol / 14.03g/mol = 5 → Molecular formula: 5×CH₂ = C₅H₁₀

B = 97.56g/mol / 14.03g/mol = 7 → Molecular formula: 7×CH₂ = C₇H₁₄

8 0

2 years ago

Adding a neutron to an atom changes what property of the atom?

brilliants [131]

Since the atomic mass consists of protons and neutrons, that would be the answer.

Answer: C. the atomic mass

3 0

3 years ago