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Rama09 [41]
3 years ago
5

What is indicated by a letter in parentheses after a chemical

Chemistry
1 answer:
Sati [7]3 years ago
4 0

The letter in parentheses after a chemical formula indicates c) the physical state of the substance.

The letters can be:

→ (s) for solid.

→ (l) for liquid.

→ (g) for gazeous.

→ (aq) for an aqueous solution (like NaCl (aq) - NaCl is dissolved in water)

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Answer:

Explanation:

"Three hundred ten million, seven hundred sixty-three thousand, one hundred thirty-six".

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The combustion of acetylene gas is represented by this equation: 2C2H2(g) + 5O2(g) → 4CO2(g) + 2H2O(g)
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Answer:

Approximately 2.46\; \rm mol.

Explanation:

Make use of the molar mass data (M({\rm C_2H_2}) = 26.04\; \rm g \cdot mol^{-1}) to calculate the number of moles of molecules in that 64.0\; \rm g of \rm C_2H_2:

\begin{aligned}n({\rm C_2H_2}) &= \frac{m({\rm C_2H_2})}{M} \\ &= \frac{64.0\; \rm g}{26.04\; \rm g\cdot mol^{-1}}\approx 2.46\; \rm mol\end{aligned}.

Make sure that the equation for this reaction is balanced.

Coefficient of \rm C_2H_2 in this equation: 2.

Coefficient of \rm H_2O in this equation: 2.

In other words, for every two moles of \rm C_2H_2 that this reaction consumes, two moles of \rm H_2O would be produced.

Equivalently, for every mole of \rm C_2H_2 that this reaction consumes, one mole of \rm H_2O would be produced.

Hence the ratio: \displaystyle \frac{n({\rm H_2O})}{n({\rm C_2H_2})} = \frac{2}{2} = 1.

Apply this ratio to find the number of moles of \rm H_2O that this reaction would have produced:

\begin{aligned}n({\rm H_2O}) &= n({\rm C_2H_2}) \cdot \frac{n({\rm H_2O})}{n({\rm C_2H_2})} \\ &\approx 2.46\; \rm mol \times 1 = 2.46\; \rm mol\end{aligned}.

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A 2-kg box is pushed from rest to a speed of 29.7 m/s in 21 seconds. What is the power require to accelerate the box.
Alona [7]

Answer:

P = 83.16 Watt

Explanation:

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Formula:

Power = work done/time

Now we will calculate the work done.

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