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Alinara [238K]
3 years ago
10

1. A compound is made up of 11 percent oxygen and 89 percent gold. What would be this compound's

Chemistry
1 answer:
bogdanovich [222]3 years ago
7 0

Answer:

Empirical formula is Au₂O₃

Explanation:

Given data:

Percentage of oxygen = 11%

Percentage of gold = 89%

Empirical formula = ?

Solution:

Solution:

Number of gram atoms of O = 11 / 16 = 0.69

Number of gram atoms of Au = 89 / 197 = 0.45

Atomic ratio:

                Au               :          O    

           0.45/0.45        :      0.69  /0.45

                    1               :           1.5      

Au  : O = 1 : 1.5

Au  : O = 2( 1 : 1.5)

Empirical formula is Au₂O₃.

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What is the kinetic energy of the emitted electrons when cesium is exposed to UV rays of frequency 1.3×1015Hz?
Sonja [21]

Answer:

We know that

ħf = ф + Ekmax  

where  

ħ = planks constant = 6.626x10^-34 J s  

f = frequency of incident light = 1.3x10^15 /s (1 Hz =

1/s)

ф = work function of the cesium = 2.14 eV  

Ekmax = max  kinetic energy of the emmitted electron.  

We distinguish that:

1 eV = 1.602x10^-19 J

So:

2.14 eV x (1.602x10^-19 J / 1 eV) = 3.428x10^-19 J

So,

Ekmax = (6.626x10^-34 J s) x (1.3x10^15 / s) - 3.428x10^-19 J

= 8.6138x10^-19 J - 3.428x10^-19 J = 5.1858x10^-19 J  

Answer:

5.19x10^-19 J  

Kinetic energy:

In physics, the kinetic energy of an object is the energy that it owns due to its motion. It is defined as the work required accelerating a body of a given mass from rest to its specified velocity. Having expanded this energy during its acceleration, the body upholds this kinetic energy lest its speed changes.

Answer details:

Subject: Chemistry

Level: College

Keywords:

• Energy  

• Kinetic energy

• Kinetic energy of emitted electrons

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Based on the "Heating Curve for Wax," what is the boiling point for wax?
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Find the grams in 1.26*10^-4 mol of HC2H3O2
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Answer:

0.00757 grams

Explanation:

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The molar mass is basically just the sum of all the atomic masses of each of the elements.

Then multiply the molar mass by the number of moles in the compound, which is 1.26 x 10^-4 moles.

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