What determines how ionic bonds will form?

Write a balanced chemical equation for the complete combustion of C3H7BO3, a gasoline additive. The products of combustion are C

nexus9112 [7]

Answer:

2C₃H₇BO₃ + 8O₂ → 6CO₂ + 7H₂O + B₂O₃.

Explanation:

For balancing a chemical equation, we should apply the law of conversation of mass. It states that the no. of atoms in the reactants side is equal to that of the products side.

So, the balanced equation:

2C₃H₇BO₃ + 8O₂ → 6CO₂ + 7H₂O + B₂O₃.

It is clear that 2.0 moles of C₃H₇BO₃ is completely burned in 8 m oles of oxygen and produce 6 moles of CO₂, 7 moles of H₂O and 1 mole of B₂O₃.

7 0

3 years ago

What is the ultimate end of a high mass star that has a core about 2.8x the mass of our sun?

jolli1 [7]

Answer:

A

Explanation:

It is formed after the star has ended its star cycle into a supernova. The star collapsed into a neutron star that is smaller than the progenitor star but has inherited angular momentum. IT, therefore, spins faster emitting electromagnetic radiation that seems to pulsate.

5 0

3 years ago

Read 2 more answers

What happens when liquid magma is cooled

Vaselesa [24]

Magma that cools quickly forms one kind of igneous rock, and magma that cools slowly forms another kind. When magma rise from deep within the earth and explodes out of a volcano, it is called lava, and it cools quickly on the surface. Rock formed in this way is called extrusive igneous rock.

6 0

3 years ago

In a transverse wave what is measured from crest to crest

galina1969 [7]

Wavelength is measured from crest to crest.

5 0

3 years ago

A ____________ alkene is more stable than a ____________ alkene because they have fewer steric interactions. In an elimination r

Vesna [10]

Answer:

See explanation

Explanation:

A trans alkene is more stable than a cis alkene because they have fewer steric interactions.

⇒ In a cis alkene there is steric hindrance, because the methyl groups are on the same side of the double bond.

Because of this steric crowding, there are van der Waals repulsive forces between the electron clouds of the groups.

This decreases the stability of the cis alkene.

In an elimination reaction, a geometry where the β hydrogen and the leaving group are on opposite sides of the molecule is called anti periplanar.

⇒ 'Anti’ refers to the two functional groups lying on opposite sides of the plane of the bond

In an SN1 mechanism, a nucleophile attacks the carbocation, forming a substitution product,

⇒ The SN1 reaction is a substitution reaction, and means "nucleophilic substitution".The "1" says that the rate-determining step is unimolecular. Thus, the rate equation is often shown as having first-order dependence on electrophile and zero-order dependence on nucleophile.

while in an E1 mechanism, a base removes a β hydrogen from the carbocation, forming a new π-bond.

⇒ E1 indicates a elimination, unimolecular reaction

This implies that the rate determining step of the mechanism depends on the decomposition of a single molecular species.

.This is a classic elimination reaction – forming a new C–C(π) bond, and breaking a C–H and C–leaving group bond.

CH3CH2Br and NaOH react by an SN2 mechanism.

⇒ It's a type of reaction mechanism that is common in organic chemistry, where one bond is broken and one bond is formed, synchronously, (in one step.)

Stronger bases, like hydroxide, favor E2 reactions, whereas weaker bases, like water favor, E1 reactions

Disubstituted alkenes always have the possibility to exist as two different Diastereomer.

Diastereomer are stereoisomers that are not mirror images of one another and are non-superimposable on one another. They exist (always) in 2 forms.

Elimination reactions are regioselective, favoring formation of the more substituted and more stable alkene.

6 0

3 years ago