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3 years ago

Compare and contrast the elements Potassium, K, and Neon, Ne. Use at least ten comparisons or descriptions.

Chemistry

1 answer:

vovikov84 [41]3 years ago

4 0

Answer:

K is a group 1 element while Ne is a group 0 element

K is a good reducing agent while Ne is inert

K is metal while Ne is a gas

K has one valence electron while Ne has no valence electron

Explanation:

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Number of miles of Xe in 12.00g of Xe

Korvikt [17]

1 mol of Xe has a mass of 131 grams
x mol of Xe has a mass of 12 grams.

1/x = 131/12 Set up proportion from the information above. Cross multiply
131x = 12 Divide by 13`
x = 12/131
x = 0.0916 mol <<<< ====

Just for fun
I don't know if a calculator would even tell me the number of miles in 12 grams of Xe

The diameter is 216 * 10^-12 meters. Maybe.
1 mol of anything is 6.02 * 10^23
0.0912 mols contain x atoms

1/0.0912 = 6.02 * 10^23 / x
x = 0.0912 * 6.02 * 10^23
x = 5.49 * 10 ^ 22 This thing is going to stretch out quite a ways.

1 atom = 312 * 10^- 12 meters.
5.049 * 10^22 = x meters.
x = 312 * 10^-12 * 5.49 * 10^22
x = 1.7 * 10 ^10 km = 1.07 * 10 ^10 miles We're talking about beyond Pluto.

I'm sorry I should delete this. If you want to you can. Take my answer for the number of mols. It's likely correct.

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4 years ago

8. What is the electron configuration of the element with 27 protons?

Komok [63]

Explanation:

Number of protons means atomic number of an atom. Element whose atomic number is 27 is cobalt.

When an atom is neutral then the number of protons equal the number of electrons.

Cobalt is a transition element or it is also known as d-block element. The electronic configuration of cobalt is as follows.

$1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{7}$

4 0

3 years ago

Please help me out on this

Damm [24]

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4 years ago

In a 0.100 m hf solution, the percent dissociation is determined to be 9.5%. calculate the ka for hf based on this data.

Elden [556K]

Answer : The dissociation constant (Ka) = 9.025 × $10^{-4}$

Solution : Given,

Concentration HF solution = 0.100 M

% Dissociation = 9.5 %

The equation for dissociation of HF is :

$HF \rightleftharpoons H^{+}+ F^{-}$

The Ka expression for HF is :

$Ka=\frac{[H^{+}][F^{-}]}{[HF]}$ ............. (1)

Step 1 : we find the $[H^{+}]$ by using the concentration and % dissociation.

$[H^{+}]$ = Concentration HF solution × % Dissociation

$[H^{+}]$ = 0.100 M × $\frac{9.5}{100}$ = 9.5 × $10^{-3}$ M

Step 2 : For $[F^{-}]$ , the concentration of $[F^{-}]$ is equal to the $[H^{+}]$ . From the above equation the stoichiometry of $[F^{-}]$ and $[H^{+}]$ is 1:1.

Therefore,

$[F^{-}]$ = $[H^{+}]$ = 0.100 M × $\frac{9.5}{100}$ = = 9.5 × $10^{-3}$ M

Now, put all the values in equation (1), we get

$Ka=\frac{(9.5\times10^{-3})\times(9.5\times10^{-3})}{(0.1)}$

= 9.025 × $10^{-4}$

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3 years ago

Compare the hardness of gypsum to an everyday substance. (site 3)

Rom4ik [11]

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3 years ago

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