Brainliest if right

(a) Find the magnitude of an earthquake that has an intensity that is 37.25 (that is, the amplitude of the seismograph reading i

MAVERICK [17]

Answer:

The magnitude of an earthquake is 5.6.

Explanation:

The magnitude of an earthquake can be found as follows:

$M = log(\frac{I}{S})$

Where:

I: is the intensity of the earthquake = 37.25 cm

S: is the intensity of a standard earthquake = 10⁻⁴ cm

Hence, the magnitude is:

$M = log(\frac{I}{S}) = log(\frac{37.25}{10^{-4}}) = 5.6$

Therefore, the magnitude of an earthquake is 5.6.

I hope it helps you!

6 0

3 years ago

In a vertical dive, a peregrine falcon can accelerate at 0.6 times the free-fall acceleration g (that is, at 0.6 g ) in reaching

anyanavicka [17]

The radius R of the turn is 1.984 km.

Explanation:

As the falcon is experiencing a centripetal motion, the acceleration exhibited by the falcon will be centripetal acceleration. The formula for centripetal acceleration is

$a=\frac{v^{2} }{R}$

Here a is the acceleration for centripetal motion, v is the velocity and R is the radius of the circular path.

As the centripetal acceleration is given as 0.6 g, the velocity is given as 108 m/s, then the radius of the path can be determined as

$0.6 \times 9.8=\frac{(108)^{2}}{R}$

$R=\frac{(108)^{2}}{0.6 \times 9.8}=\frac{11664}{5.88}=1983.67\ \mathrm{m}$

So, the radius of the turn is 1.984 km.

6 0

3 years ago

How many sig figs are in 0.32

jarptica [38.1K]

2 significant figures

5 0

3 years ago

What is happening to the average kinetic energy of the molecules in a pot of water when it is heated on a stove? Explain your an

Pepsi [2]

Answer:

Explanation:

The average kinetic energy of molecules in a pot increases when it is heated on a stove . The heat energy is spent to decrease the intermolecular attractive force . The result is increase in kinetic energy due to increase in the velocity of molecules

formula for kinetic energy of one mole of a monoatomic gas

= 3/2 RT

when temperature increases , kinetic energy increases .

6 0

3 years ago

The primary reason a light bulb emits light is due to

Mashutka [201]

The primary reason a light bulb emits light is due to the heating of the resistance in the filament of the light bulb. In fact, the power dissipated in a resistor is given by
 $P=I^2 R$
where I is the current and R the resistance. The larger the resistance or the current in the resistor, the larger the power dissipated. Due to this dissipation of power, the temperature of the filament becomes very high, and the resistance becomes incandescent, emitting light.

5 0

4 years ago

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