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Luden [163]
3 years ago
13

Brainliest if right

Physics
1 answer:
mixas84 [53]3 years ago
3 0
They traveling at -0.37/ms^
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Starting fom rest, a car accelerates at a constant rate, reaching 88 km/h in 12 s. (a) What is its acceleration? (b) How far doe
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Answer:

(A)  a=2.0.37m/sec^2

(B) s = 146.664 m

Explanation:

We have given car starts from the rest so initial velocity u = 0 m /sec

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We know that 1 km = 1000 m

And 1 hour = 3600 sec

So 88km/hr=88\times \frac{1000}{3600}=24.444m/sec

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(A) From first equation of motion v = u+at

So 24.444=0+a\times 12

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So acceleration of the car will be a=2.0.37m/sec^2

(b) From third equation of motion v^2=u^2+2as

So 24.444^2=0^2+2\times 2.037\times s

s = 146.664 m

Distance traveled by the car in this interval will be 146.664 m

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