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iris [78.8K]
2 years ago
10

What is a solvent ?

Chemistry
1 answer:
pantera1 [17]2 years ago
3 0

Answer:

A solvent is a substance that dissolves a solute, resulting in a solution. A solvent is usually a liquid but can also be a solid, a gas, or a supercritical fluid.

Explanation:

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Which instrument is used to observe space system from Earth?
Vlad [161]

Answer:

The telescope is used.

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Waste water from nuclear power plants is generally
FrozenT [24]

Answer:

waste water from nuclear power plant is

generally very harmful for our environment

and for everyone

hope it will help

4 0
2 years ago
30cm^3 of a dilute solution of Ca(OH)2 required 11 cm^3 of 0.06 mol/dm^. Hcl for complete neutralization. Calculate the concentr
Alenkasestr [34]

Answer: Thus concentration of Ca(OH)_2 in mol/dm^3  is 0.011 and in g/dm^3 is 0.814

Explanation:

To calculate the concentration of Ca(OH)_2, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HCl

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is Ca(OH)_2

We are given:

n_1=1\\M_1=0.06mol/dm^3\\V_1=11cm^3=0.011dm^3\\n_2=2\\M_2=?\\V_2=30cm^3=0.030dm^3         1cm^3=0.001dm^3

Putting values in above equation, we get:

1\times 0.06mol/dm^3\times 0.011dm^3=2\times M_2\times 0.030dm^3\\\\M_2=0.011mol/dm^3

The concentration in g/dm^3 is 0.011mol/dm^3\times 74g/mol=0.814g/dm^3

Thus concentration of Ca(OH)_2 is 0.011mol/dm^3 and 0.814g/dm^3

4 0
3 years ago
Fill in the blank. A ___ is a substance that cannot be separated into simpler substances by physical or mechanical methods such
Ganezh [65]
An element cannot be broken down any further. Elements can be found on the periodic table

8 0
3 years ago
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16. A solution is made by dissolving 25 g of NaCl in enough water to make 1.0 L of solution. Assume the density of the solution
nata0808 [166]

Answer:

The molarity will be "0.43 M" and molality will be "0.43 m".

Explanation:

Given that:

mass of NaCl,

= 25 g

Volume of solution,

= 1 L

Density of solution,

= 1 gm/cm³

Now,

The weight of solvent will be:

= Volume\times density

= 1\times 1

= 1 \ kg

The mole of NaCl will be:

= \frac{mass}{Molar \ mass}

= \frac{25}{58.44}

= 0.43

hence,

The molarity will be:

= \frac{number \ of \ mole}{Volume \ of \ solution}

= \frac{0.43}{1}

= 0.43 \ M

The molality will be:

= \frac{mole \ of \ solute}{Weight \ of \ solvent}

= \frac{0.43}{1}

= 0.43 \ m

4 0
2 years ago
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