When calcium joins with calcium its follows the following equation:
2Ca + O2 = 2CaO
hope that helps
Answer:
Final mass = 159.5 g
Final temperature = 10 C
Final density = 1.00 g/ml
Explanation:
<u>Given:</u>
Beaker 1:
Mass of water = 44.3 g
Temperature = 10 C
Beaker 2:
Mass of water = 115.2 g
Temperature = 10 C
Density of water at 10C = 1.00 g/ml
<u>To determine:</u>
The final mass, temperature and density of water
<u>Calculation:</u>

Since there is no change in temperature, the final temperature will be 10 C
Density of a substance is an intensive property i.e. it is independent of the mass. Hence the density of water will remain constant i.e. 1.00 g/ml
T₁ = 50,14 K.
p₁ = 258,9 torr.
T₂ = 161,2 K.
p₂ = 277,5 torr.
R = 8,314 J/K·mol.
Using Clausius-Clapeyron equation:
ln(p₁/p₂) = - ΔHvap/R · (1/T₁ - 1/T₂).
ln(258,9 torr/277,5 torr) = -ΔHvap/8,314 J/K·mol · (1/50,14 K - 1/161,2 K).
-0,069 = -ΔHvap/8,314 J/K·mol · (0,0199 1/K - 0,0062 1/K).
0,0137·ΔHvap = 0,573 J/mol.
ΔHvap = 41,82 J.