Given :
A wrecking ball of mass 500 kg hangs form a crane by a cable of length 25 m
this wrecking ball is released from an angle of 40 degrees.
To Find :
The height from the lowest point of the arc.
Solution :
From the attached image we have to find the value of h.
So,
Hence, this is the required solution.
Use the conservation of the momentum to answer this question:
The resulting speed of the two bodies will be 2.2 m/s in the (original) direction of the overweight guy (110kg). Their brains not happy about the collision either.
(a) At level A Potential Energy is 2940 J.
(b) At level B Potential Energy is 1960 J.
(c) At level C Potential energy is 1470 J.
(d) At level D Potential energy is 0 J.
(e) The change in Potential energy if the object moves from A to B is 980 J.
<u>Explanation</u>:
Given that,
Mass of an object is 5 kg (m) at a height of 60 m (h) above the ground as shown in the given figure.
Potential energy of an object is calculated by using the formula m × g × h. “g” is acceleration due to gravity on earth is 9.8 .
(a) At level A:
At height (h) is 60 m above ground.
Potential energy = 5 × 9.8 × 60
Potential energy = 2940 J
(b) At level B:
At height (h) is 40 m above ground.
Potential energy = 5 × 9.8 × 40
Potential energy = 1960 J
(c) At level C:
At height (h) is 30 m above ground.
Potential energy = 5 × 9.8 × 30
Potential energy = 1470 J
(d) At level D:
At height (h) is 0 m above ground (object is on the ground).
Potential energy = 5 × 9.8 × 0
Potential energy = 0 J
(e) Change in “Potential energy” when it moves from “A” to “B”
Change in “Potential energy” in difference in initial “Potential energy” (at level A) and final “Potential energy” (at level B)
= 2940 - 1960
= 980 J
Therefore, change in “Potential energy” is 980 J.