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alisha [4.7K]
3 years ago
12

Someone help me with this

Physics
1 answer:
vampirchik [111]3 years ago
4 0

Answer:

All reactions listed are of synthesis type.

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Rectangular plate has a voltage of +180V and plate to the first plate) has a 'voltage of -5V. Determie another rectangular plate
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For a Rectangular plate has a voltage of +180V and a 'voltage of -5V. , the second plate has the Electric field mathematically given as

E=21.5*10^3v/m

<h3>What is the field strength?</h3>

Generally, the equation for the Electric field   is mathematically given as

E=v/d

Where

v={180-(-5)}v

v=185v

Therefore

E=185/8.6*10^{-3}

E=21.5*10^3v/m

In conclusion, Electric field

E=21.5*10^3v/m

Read more about electric field

brainly.com/question/9383604

4 0
2 years ago
1. If a model train car with a momentum of 12 kg•m/s collides with a 2 kg model train car that is not moving, what is the total
wariber [46]

Answer:

P_{f} = 12 \ kg.m/s

Explanation:

Given data:

Momentum of moving model train, P_{1} = 12 \ kg.m/s

Mass of the stationary model train, m = 2 \ kg

Initial speed of the stationary model train, v = 0

Assume there is no external force is acting on the given train system.

In this case, the total linear momentum of the trains would be conserved.

Let the final linear momentum of the trains be P_{f}.

Thus,

P_{i} = P_{f}

P_{1} + P_{2} = P_{f}

P_{1} + mv = P_{f}

12 + 2 \times 0 = P_{f}

\Rightarrow \ P_{f} = 12 \ kg.m/s.

7 0
3 years ago
What is the freezing point of an aqueous solution that boils at 101 degrees C? Kfp = 1.86 K/m and Kbp = 0.512 K/m. Enter your an
astra-53 [7]

Answer:

-3.63 degree Celsius

Explanation:

We are given that

Boiling point of solution=T_b=101^{\circ} C

Boiling point water=100 degree Celsius

K_f=1.86K/m

K_b=0.512 K/m

\Delta T_b=T-T_0

Where T=Boiling point of solution

T_0=Boiling point of pure solvent

\Delta T_b=101-100=1^{\circ}C

\Delta T_b=k_bm

Using the formula

1=0.512\times m

Molality,m=\frac{1}{0.512} m

\Delta T_f=k_fm

Using the formula

\Delta T_f=\frac{1}{0.512}\times 1.86

\Delta T_f=3.63 C

We know that

\Delta T_f=T_0-T_1

Where T_0 =Freezing point of solvent

T_1= Freezing point of solution

Using the formula

3.63=0-T_1

Freezing point of water=0 degree Celsius

T_1=0-3.63=-3.63 C

Hence, the freezing point of solution=-3.63 degree Celsius

7 0
2 years ago
What style of art represents people or objects exactly as they appear in life?
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REALISM shows things as they REALLY look.
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3 years ago
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Convert 500,000 inches into miles
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3 years ago
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