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2 years ago

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Rectangular plate has a voltage of +180V and plate to the first plate) has a 'voltage of -5V. Determie another rectangular plate

(parallel to between these two plates? The distance of the field strength at any point separation of the plates is finite, say 8.6mm.

1 answer:

3241004551 [841]2 years ago

4 0

For a Rectangular plate has a voltage of +180V and a 'voltage of -5V. , the second plate has the Electric field mathematically given as

E=21.5*10^3v/m

<h3>What is the field strength?</h3>

Generally, the equation for the Electric field is mathematically given as

E=v/d

Where

v={180-(-5)}v

v=185v

Therefore

E=185/8.6*10^{-3}

E=21.5*10^3v/m

In conclusion, Electric field

E=21.5*10^3v/m

Read more about electric field

brainly.com/question/9383604

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Answer:

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Explanation:

Given that,

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Time = 3.25 sec

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Put the value into the formula

$d=20\cos40\times3.25$

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Using formula of velocity

$v_{x}=u\cos\theta$

Put the value into the formula

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Using equation of motion

$v_{y}=u\sin\theta-gt$

Put the value into the formula

$v_{y}=20\sin40-9.8\times3.25$

$v_{y}=-19\ m/s$

Negative sign shows the opposite direction.

We need to calculate the speed of ball

Using formula of speed

$v=\sqrt{v_{x}^2+v_{y}^2}$

$v=\sqrt{(15.3)^2+(19)^2}$

$v=24.39\ m/s$

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Answer:

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Explanation:

For this case we have the following system with the forces on the figure attached.

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Part b

For this case first we can convert the spring constant to N/m like this:

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And the work donde by the spring on this case is given by:

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Let d1 represent the new maximum distance, in order to find it we know that :

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And replacing we got:

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If we multiply all the equation by 2 we got:

$k d^2_1 -2 mg d_1 -m V^2_i =0$

Now we can replace the values and we got:

$200N/m d^2_1 -0.21kg(9.8m/s^2)d_1 -0.21 kg(5.50 m/s)^2) =0$

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