Ask question

Ask question

All categories

3 years ago

14

Type your answer in decimal form. Do not round. 7 days = hours

2 answers:

denpristay [2]3 years ago

8 0

Explanation:
Solar day:
1

day

=
24
h

7

day
=
7
⋅
24
h
=
168
h

Stellar day:
1

day

=

23

hours

56

minutes

and

4.1

seconds

=

djyliett [7]3 years ago

5 0

168.0
Hope this helps u

You might be interested in

It's #9 Pls help will give 100 points and brainiest

Vinil7 [7]

heating is repeated to ensure all water molecules have evaporated

7 0

2 years ago

If 18.7ml of 0.01500M aqueous HCl is required to titrâtes 15.00ml of an aqueous solution of NaOH to the equivalence point, what

sweet [91]

Answer:

0.0187 M

Explanation:

Step 1: Write the balanced neutralization reaction

NaOH + HCl ⇒ NaCl + H₂O

Step 2: Calculate the reacting moles of HCl

18.7 mL of 0.01500 M HCl react.

0.0187 L × 0.01500 mol/L = 2.81 × 10⁻⁴ mol

Step 3: Calculate the reacting moles of NaOH

The molar ratio of HCl to NaOH is 1:1. The reacting moles of NaOH are 1/1 × 2.81 × 10⁻⁴ mol = 2.81 × 10⁻⁴ mol.

Step 4: Calculate the molarity of NaOH

2.81 × 10⁻⁴ moles are in 15.00 mL of NaOH.

[NaOH] = 2.81 × 10⁻⁴ mol/0.01500 L = 0.0187 M

6 0

3 years ago

Green light has a wavelength of 550nm. What is the frequency of a photon of green light?

Vikki [24]

Answer:- Frequency is $5.4*10^1^4Hz$ .

Solution:- frequency and wavelength are inversely proportional to each other and the equation used is:

$\nu =\frac{c}{\lambda }$

where, $\nu$ is frequency, c is speed of light and $\lambda$ is the wavelength.

Speed of light is $3.0*10^8m/s$ .

We need to convert the wavelength from nm to m.

( $1nm=10^-^9m$ )

$550nm(\frac{10^-^9m}{1nm})$

= $5.5*10^-^7m$

Now, let's plug in the values in the equation to calculate the frequency:

$\nu =\frac{3.0*10^8m.s^-^1}{5.5*10^-^7m}$

= $5.4*10^1^4s^-^1$ or $5.4*10^1^4Hz$

since, $1s^-^1=1Hz$

So, the frequency of the green light photon is $5.4*10^1^4Hz$ .

4 0

3 years ago

The ____ are new substances that are created following a chemical reaction. *

KonstantinChe [14]

Answer:

b

Explanation:

8 0

3 years ago

Assuming the boiling point increased by 2 Â°C, what is the approximate molality of NaCl when the video ends? Kbp(water) = 0.512

makkiz [27]

Answer : The molality of NaCl is, 1.95 mol/kg

Explanation :

Formula used for Elevation in boiling point :

$\Delta T_b=i\times k_b\times m$

where,

$\Delta T_b$ = change in boiling point = $2^oC$

$k_b$ = boiling point constant for water = $0.512^oC/m$

m = molality

i = Van't Hoff factor = 2 (for electrolyte)

The dissociation $NaCl$ will be,

$NaCl\rightarrow Na^++Cl^{-}$

So, Van't Hoff factor = Number of solute particles = $Na^++Cl^{-}$ = 1 + 1 = 2

Now put all the given values in the above formula, we get:

$2^oC=2\times (0.512^oC/m)\times m$

$m=1.95mol/kg$

Therefore, the molality of NaCl is, 1.95 mol/kg

6 0

3 years ago