Answer:1.16 rad/s
Explanation:
Given
radius of circular path(r)=7.20 m
let be the angular velocity of ride
and centripetal acceleration is given by
which should be equal to gravity(g)
Answer:
A. 0.20 unpolarized and 0.80 plane polarized.
Explanation:
After passing through polaroid sheet , unpolarised portion will get reduced by half . So this portion becomes .20/ 2 = 0.10
The polarized portion can face two situation depending upon the angle of the polaroid.
It may either be cut off to zero. So total intensity of transmitted light wil be .10 + 0 = .10
It may or be passed fully . In that case total intensity of transmitted light will become 0 .10 +0.80 =0.90
Ratio of these two light of maximum and minimum intensity is 0.90 / 0.10 = 9.
The gravitational acceleration on the surface of planet A is:
where G is the gravitational constant,
is the mass of planet A and
its radius.
Similarly, the gravitational acceleration on the surface of planet B is:
The ratio between the gravitational acceleration on planet A and B becomes:
The problem says that the two masses are equal:
while planet A has 3 times the radius of planet B:
. Substituting into the ratio, we get:
so, gravity on planet B is 9 times stronger than planet A.
Answer:
ωf = 4.53 rad/s
Explanation:
By conservation of the angular momentum:
Ib*ωb = (Ib + Ic)*ωf
Where
Ib is the inertia of the ball
ωb is the initial angular velocity of the ball
Ic is the inertia of the catcher
ωf is the final angular velocity of the system
We need to calculate first Ib, Ic, ωb:
ωb = Vb / (L/2) = 16 / (1.2/2) = 26.67 m/s
Now, ωf will be:
I think the distance that should be used is the distance that one expects to be from the game you are hunting. Before taking a shotgun for a gobbler or even for ducks or other animals, you need to see how your gun performs by patterning it at various ranges with the load you want to use.