Two objects, each of mass 2 kg, are moving in the same straight line but in opposite directions. They are moving with velocities
1 answer:
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Consider the east-west direction along x-axis and north-south direction along y-axis. In unit vector notation, velocities can be given as
= velocity of car A before collision = 0 i -
j
= velocity of car B before collision =
i + 0 j
= velocity of combination after collision = (35.8 Cos31.6) i - (35.8 Sin31.6) j = 30.5 i - 18.8 j
= mass of car A = 1750 kg
= mass of car B = 1450 kg
Using conservation of momentum
+
= (
+
) (
)
(1750) (0 i - j) + (1450) (
i + 0 j) = (1750 + 1450) (30.5 i - 18.8 j)
(1450) i - (1750)
j = 97600 i - 60160 j
Comparing the coefficient of "i" and "j" both side
(1450) = 97600 and - (1750)
= - 60160
= 67.3 km/h and
= 34.4 km/
Answer:
The magnitude of the total linear acceleration is 0.27 m/s²
b. 0.27 m/s²
Explanation:
The total linear acceleration is the vector sum of the tangential acceleration and radial acceleration.
The radial acceleration is given by;
where;
a is the angular acceleration and
r is the radius of the circular path
Determine time of the rotation;
Determine angular velocity
ω = at
ω = 1.6 x 0.707
ω = 1.131 rad/s
Now, determine the radial acceleration
The magnitude of total linear acceleration is given by;
Therefore, the magnitude of the total linear acceleration is 0.27 m/s²
b. 0.27 m/s²