1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ehidna [41]
3 years ago
10

Two objects, each of mass 2 kg, are moving in the same straight line but in opposite directions. They are moving with velocities

10 m/s and 5 m/s respectively before the collision during which they stick together. The velocity of the combined object after collision is,
Physics
1 answer:
ANEK [815]3 years ago
7 0

Answer:

2.5m/s

Explanation:

Using the law of conservation of energy;

m1u1 + m2u2 = (m1+m2)v

m1 and m2 are the masses

u1 and u2 are the initial velocities

v is the final velocity

Substitute the given values in the formula

2(10)-2(5) = (2+2)v

20-10 = 4v

10 = 4v

v = 10/4

v = 2.5m/s

Hence the velocity of the combined object after collision is 2.5m/s

You might be interested in
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! I CANNOT RETAKE THIS!!
scoray [572]
Jim walks 7 miles from the starting point to the end point
i guess so
3 0
4 years ago
Read 2 more answers
The law of conservation of momentum states that the total momentum of interacting objects does not _______. This means the total
Nata [24]

Explanation:

Law of conservation of momentum states that in an isolated system when two objects collide with each other then total momentum before and after the collision is equal.

Thus, we can conclude that the law of conservation of momentum states that the total momentum of interacting objects does not change. This means the total momentum before a collision or explosion is equal to the to momentum after a collision or explosion.

5 0
3 years ago
Read 2 more answers
The 94-lb force P is applied to the 220-lb crate, which is stationary before the force is applied. Determine the magnitude and d
Makovka662 [10]

Answer

given,

force = 94 lb

weight of crate = 220 lb

Assuming the static friction be equal = 0.47

                       kinetic friction = 0.36

Maximum force applied to move the object is when object is just start to move.

F = μ N

F = 0.47 x 220

F = 103.4 lb

As the frictional force is more than applied then the object will not move.

so, the friction force will be equal to the force applied on the object that is equal to 94 lb.

hence, the direction of force will left.

8 0
3 years ago
A man walks 30 m to the west, then 5 m to the east in 45 seconds.
katen-ka-za [31]

Answer:

a. Displacement=30²+5²=925= 30.4m

b. Total distance=30m+5m=35m

c. V=s/t. = 30.4/45=0.6m/s

8 0
2 years ago
A concave mirror is diverging mirror.true or false​
marissa [1.9K]

Answer:

true

Explanation:

it is concave when it diverging

4 0
3 years ago
Other questions:
  • At one particular moment, a 15.0 kg toboggan is moving over a horizontal surface of snow at 4.40 m/s. After 7.50 s have elapsed,
    11·1 answer
  • A 20-kilogram mass is traveling with a velocity of 3 m/s. What is the object's kinetic energy?
    12·1 answer
  • Two sources of in-phase coherent sound are located at the points (0 m, 2 m) and (-2 m, 0 m). An observer at the origin hears con
    14·1 answer
  • A ladder 10 ft long rests against a vertical wall. If the bottom of the ladder slides away from the wall at a rate of 1.5 ft/s,
    15·1 answer
  • An object's motion changes A. only if the object is at rest when a force acts upon it. B. only when a nonzero net force is appli
    6·1 answer
  • A function is defined by f(x)= 6x+1.5. What is f(2.5)?
    9·1 answer
  • Manita carries a box of mass 40 kg.what is the weight<br>​
    10·1 answer
  • PLEASE ANSWER IF YOU CAN AND NOT FOR THE SAKE OF GAINING POINTS!
    11·1 answer
  • PLEASE HELP THIS IS DUE IN 15 MINS
    15·1 answer
  • When a new path of lesser resistance is made for an existing circuit a(n) _____________ circuit occurs.
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!