Answer:
Morning's average rate = 50 mph, and Afternoon's average rate = 25 mph.
Step-by-step explanation:
Suppose he drove 150 miles for X hours, then his average rate in the morning was (150/X) mph.
Given that he spent 5 hours in driving.
And he drove 50 miles for (5-X) hours, then his average rate in the afternoon was 50/(5-X) mph.
Given that his average rate in the morning was twice his average rate in the afternoon.
(150/x) = 2 * 50/(5-x)
150/x = 100/(5-x)
Cross multiplying terms, we get:-
150*(5-x) = 100*x
750 - 150x = 100x
750 = 100x + 150x
750 = 250x
x = 750/250 = 3.
It means he spent 3 hours in the morning and 2 hours in the afternoon.
So morning's average rate = 150/3 = 50 mph.
and afternoon's average rate = 50/(5-3) = 25 mph.
B. All sides are equal and each side is at a 60 degree angle.
I believe, if I'm not correct but I think the answer would be 8 minutes or less.. Considering the fact that the Harris Family left 12 minutes ahead and the Arlen family is Averaging 55 MPH.. Too the speed that the Arlen's are going make the time for them to catch up to the harris's shorter. The Arlen's are going 15 mph faster sooo.. Yeah.. Tell em if this helps! :D
Answer: 0.0668073
Step-by-step explanation:
Given : The number of miles each tire lasts before it completely wares out follows a normal distribution with mean μ = 50,000 miles and standard deviation σ = 8,000 miles.
Let x be the random variable that represents the number of miles each tire lasts.
z-score : 
For x= 62,000
By using the standard z-value table , the probability for a randomly selected tire to last for at least 62,000 miles will be :_
Hence, the probability for a randomly selected tire to last for at least 62,000 miles = 0.0668073
Answer:
g(x) = (x - 1)^2 + 2.
Step-by-step explanation:
1 unit to the right x---> (x - 1)
2 units up ------ f(x) moves up ---> + 2
answer is (x - 1)^2 + 2
