Question

according to the recipe for soap in the background 1 gallon of lye solution was required for 2 pounds of fat. how many liters are there in 1.00 gallon? how many grams are there in 2.00 pounds?​

Answer 1

Answer:

3.785 L of lye solution needed  for 907.185 g of fat

Explanation:

The computation of the number of grams in 2.00 pounds is shown below:

As we know that

One gallon of lye solution needed 2 fats pounds

Also,

1 gallon = 3.785 L

And,

1 lb = 453.592 g

So,

For 2 lb, it is

= 2 × 453.592

= 907.185 g

Therefore  

3.785 L of lye solution needed  for 907.185 g of fat

hence, the same is to be considered