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zvonat [6]
3 years ago
10

according to the recipe for soap in the background 1 gallon of lye solution was required for 2 pounds of fat. how many liters ar

e there in 1.00 gallon? how many grams are there in 2.00 pounds?​
Chemistry
1 answer:
yawa3891 [41]3 years ago
3 0

Answer:

3.785 L of lye solution needed  for 907.185 g of fat

Explanation:

The computation of the number of grams in 2.00 pounds is shown below:

As we know that

One gallon of lye solution needed 2 fats pounds

Also,

1 gallon = 3.785 L

And,

1 lb = 453.592 g

So,

For 2 lb, it is

= 2 × 453.592

= 907.185 g

Therefore  

3.785 L of lye solution needed  for 907.185 g of fat

hence, the same is to be considered

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0.500 L of a gas is collected at 2911 MM and 0°C. What will the volume be at STP?
ioda

Answer:

V₂ =  1.92 L

Explanation:

Given data:

Initial volume = 0.500 L

Initial pressure =2911 mmHg (2911/760 = 3.83 atm)

Initial temperature = 0 °C (0 +273 = 273 K)

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Solution:

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

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by putting values,

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 3.83 atm × 0.500 L × 273 K / 273 K × 1 atm

V₂ = 522.795 atm .L. K / 273 K.atm

V₂ =  1.92 L

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Answer:

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