Moles of Oxygen= 2.8075 moles
<h3>Further explanation</h3>
Given
29.2 grams of acetylene
Required
moles of Oxygen
Solution
Reaction(Combustion of Acetylene) :
2 C₂H₂ (g) + 5 O₂ (g) ⇒ 4CO₂ (g) + 2H₂O (g)
Mol of Acetylene :
= mass : MW Acetylene
= 29.2 g : 26 g/mol
= 1.123
From equation, mol ratio of Acetylene(C₂H₂) : O₂ = 2 : 5, so mol O₂ :
= 5/2 x mol C₂H₂
= 5/2 x 1.123
= 2.8075 moles
<u>Answer:</u> The percent composition of hydrogen in the sample is 15.22 %
<u>Explanation:</u>
We are given:
Mass of hydrogen = 7 grams
Mass of nitrogen = 32 grams
Mass of carbon = 7 grams
Total mass of the sample = 7 + 32 + 7 = 46 grams
To calculate the percentage composition of hydrogen in sample, we use the equation:
Mass of sample = 46 g
Mass of hydrogen = 7 g
Putting values in above equation, we get:
Hence, the percent composition of hydrogen in the sample is 15.22 %
Answer:
465mL
Explanation:
Volume of a solution, V =Mass of substance, m/(Molarity of the solution of the substance, M × molar mass of the substance, M.m)
Given in the question,
M=.132M
M.m=23+35.5 = 58.5g/mol
m=3.59g
V= 3.59/(.132×58.5)
V = 0.465L
Volume in mL = volume in L × 1000
= 0.465 × 1000 = 465mL
Therefore, 465mL of a .132M aqueous solution of sodium chloride, NaCl, must be taken to obtain 3.59 grams of the salt
Answer:44.04mL
Explanation:Parameters given
V1 = 30.0mL
P1 = 36.7psi
P2 = 25.0psi
V2 = ??
From Boyle's gas law, which states that "the pressure of a given mass of an ideal gas is inversely proportional to its volume at a constant temperature"
This means that,
the pressure of a gas tends to increase as the volume of the container decreases, and also the pressure of a gas tends to decrease as the volume of the container increases.
Mathematically, Boyle's can be represented as shown below
P= k/V
Where P = Pressure, V = Volume and k is constant
Therefore,
PV = k
P1V1 = P2V2 =PnVn
Using the formula
P1V1 = P2V2
V2 = P1V1/P2
V2 = (36.7psi × 30.0mL) / 25.0psi
V2 = 1101.0/25.0
V2 = 44.04mL
