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Crazy boy [7]
3 years ago
5

Which of the following groups of elements are likely to be radioactive? (5 points) a Actinides b Noble gases c Transition metals

d BCNOs
Chemistry
1 answer:
Nataly [62]3 years ago
3 0

Answer:

Actinides

Explanation:

They are defined as "any of the series of fifteen metallic elements from actinium (atomic number 89) to lawrencium (atomic number 103) in the periodic table. They are all radioactive, the heavier members being extremely unstable and not of natural occurrence"

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Campare and Conteast Physical and chemical properties.
I am Lyosha [343]

Answer:

Physical properties are changes in color, weight, mass, density, volume, whether it is freezing, tarnishing, boiling, etc. while chemical properties are changes in the compound of the object such as whether an object is/isn't flammable, affected by acid, it dissolves, ferments, rots, ignites in water, etc.

Explanation:

Physical property examples: a piece of steel is cut in half, a sugar cube is ground up into a powder, ice melts into water, clouds form in the sky, you mow the lawn, the water turned purple when you dropped red and blue dye in it, leaves grow in the spring, ethyl alcohol boils at 79° C, you cut apples up

Chemical property examples: pancakes cook on the griddle, fireworks explode in th sky, Alka-Seltzer gives off carbon dioxide when added to water, roasting a marshmellow, milk sours when left on the counter, burning wood in a bonfire, salt dissolves in water, food is digested in the stomach

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How many valence electrons are in a silicon atom?
vladimir1956 [14]
Four valence electron
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4 years ago
Describe what you should do to recover only the water from a sample of muddy water.<br>​
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By using a filter.

Explanation:

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3 years ago
Read 2 more answers
Calculate the specific heat of a piece of wood if 2000 g of wood absorbs 75,250 J of heat, and its temperature changes from 30°C
inna [77]

Answer:

C

Explanation:

<em>The </em><em>specific</em><em> </em><em>heat </em><em>capacity</em><em>=</em><em>quantity</em><em> of</em><em> </em><em>heat</em><em> </em><em>in </em><em>joule/</em><em>mass×</em><em>c</em><em>h</em><em>a</em><em>n</em><em>g</em><em>e</em><em> </em><em>in </em><em>temperature</em>

<em>from </em><em>this </em><em>question</em><em> </em><em>the </em><em>quantity</em><em> of</em><em> </em><em>heat</em><em> </em><em>is </em><em>7</em><em>5</em><em>2</em><em>5</em><em>0</em><em>,</em><em>the </em><em>mass </em><em>is </em><em>2</em><em>0</em><em>0</em><em>0</em><em> </em><em>and </em><em>the </em><em>change </em><em>in </em><em>temperature</em><em> </em><em>is </em><em>5</em><em>0</em><em>-</em><em>3</em><em>0</em>

<em>which </em><em>is </em><em>2</em><em>0</em>

<em>therefore</em>

<em>c=</em><em>7</em><em>5</em><em>2</em><em>5</em><em>0</em><em>/</em><em>2</em><em>0</em><em>0</em><em>0</em><em>×</em><em>2</em><em>0</em>

<em>c=</em><em>7</em><em>5</em><em>2</em><em>5</em><em>0</em><em>/</em><em>4</em><em>0</em><em>0</em><em>0</em><em>0</em>

<em>c=</em><em>1</em><em>.</em><em>8</em><em>8</em>

<em>I </em><em>hope </em><em>this </em><em>helps</em>

3 0
3 years ago
An unbalanced equation is shown. In this reaction, 200.0 g of FeS2 is burned in 100.0 g of oxygen, and 55.00 g of Fe2O3 is produ
Crazy boy [7]
<span>4FeS2 + 11O2 = 2Fe2O3 + 8SO2</span>

Percent yield is calculated as the actual yield divided by the theoretical yield multiplied by 100.

Actual yield = 55 g ( 1 mol / 159.69 g ) = 0.34 mol Fe2O3

To find for the theoretical yield, we first determine the limiting reactant.

100 g O2 ( 1 mol / 32 g) = 3.13 mol O2
200 g FeS2 (1 mol / 119.98g) = 1.67 mol FeS2

Therefore, the limiting reactant is O2.

Theoretical yield = 3.13 mol O2 ( 2 mol Fe2O3 / 11 mol O2 ) = 0.57 mol Fe2O3

Percent yield = (0.34 mol / 0.57 mol) x 100 = 59.74%
3 0
3 years ago
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