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san4es73 [151]
3 years ago
8

Joseph drives 25miles North in 15 minutes then he drives 40 miles east in 30 minutes, then he uses cruise control option for 1 h

our and covers 70 miles on the highway and finally drives 15 miles in 15 minutes. What was his average speed?
Chemistry
1 answer:
Musya8 [376]3 years ago
7 0

Answer: 1.25 miles per minute

Explanation:

Average speed is the rate of change of total distance covered per unit time.

i.e Average speed = (Total distance / Time taken)

Total distance covered = (25miles + 40 miles + 70 miles + 15 miles)

= 150 miles

Total time taken = ( 15 minutes + 30 minutes + 1 hour + 15 minutes) = 120 minutes

Since 60 minutes = 1 hour, the total time taken is 120 minutes

Now, apply Average speed = (Total distance / Time taken)

= (150 miles / 120 minutes)

= 1.25 miles per minutes

Thus, Joseph drove with an average speed of 1.25 miles per minute.

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Explanation:

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3 years ago
What is the molarity of a stock solution if 60 mL were used to make 150 ml<br>of a .5M solution? ​
olga2289 [7]

The molarity of the stock solution is 1.25 M.

<u>Explanation:</u>

We have to find the molarity of the stock solution using the law of volumetric analysis as,

V1M1 = V2M2

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M1 = 0.5 M

V2 = 60 ml

M2 = ?

The above equation can be rearranged to get M2 as,

M2 = $\frac{V1M1}{V2}

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M2 = $\frac{150 \times 0.5}{60}

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4 0
3 years ago
Can you help me with this problem?
wolverine [178]

Answer:

0.504 mol Ag

Explanation:

First find the moles of copper in 16g

The molar mass of Cu is: 63.546

Therefore there are .252 moles in 16g as shown by this equation:

16/63.546 = .252

The mole ratio of Cu to Ag is 1 to 2

So we can simply multiply the moles of Cu by 2/1 to find the moles of Ag

We found .252 already so we multiply it by 2 and find that the reaction produces .504 moles of Ag

4 0
3 years ago
Which set of measurements correctly identifies the speed of an object?
In-s [12.5K]

Answer:

A. Distance = 18 m

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For choice B, the numbers are right, but the units are mixed (minutes were changed to hours)

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